A^2 + b^2 = c^2
9^2 + 2^2 = c^2
81 + 4 = c^2
85 = c^2
take the square root of 82 which equals 9.05538…
if it wants a whole number then 10, but if it wants a decimal, the. 9.6 ft.
if you need more detail lmk :)
The value of c, the constant of the function y = ax² + bx + c, exists -3.
<h3>What is an equation?</h3>
An equation exists as an expression that indicates the relationship between two or more numbers and variables.
Given that: y = ax² + bx + c
At point (4, 21)
21 = a(4²) + 4b + c .......(1)
At point (5, 32)
32 = a(5²) + 5b + c .........(2)
At points (6, 45)
45 = a(6²) + 6b + c .......(3)
Therefore, the value of a = 1, b = 2 and c = -3.
The value of c, the constant of the function y = ax² + bx + c, exists -3.
To learn more about equations refer to:
brainly.com/question/2972832
#SPJ9
A recursive rule for a geometric sequence:
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The exciplit rule:
Substitute:
A parabola is a quadratic function, and a quadratic can be expressed in vertex form, which is:
y=a(x-h)^2+k, where (h,k) is the vertex (absolute maximum or minimum point of the quadratic)
In this case we are given that (h,k) is (-5,80) so we have so far:
y=a(x--5)^2+80
y=a(x+5)^2+80, we are also told that it passes through the point (0,-45) so:
-45=a(0+5)^2+80
-45=25a+80 subtract 80 from both sides
-125=25a divide both sides by 25
-5=a, so now we know the complete vertex form is:
y=-5(x+5)^2+80
The x-intercepts occur when y=0 so:
0=-5(x+5)^2+80 add 5(x+5)^2 to both sides
5(x+5)^2=80 divide both sides by 5
(x+5)^2=16 take the square root of both sides
x+5=±√16 which is
x+5=±4 subtract 5 from both sides
x=-5±4 so the x-intercepts are:
x=-1 and -9
