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svet-max [94.6K]

3 years ago

5

Lisa used 1/4 cup of milk per batch using her muffin recipe. How many cups of milk did she use when she made 6 batches of muffin

s?

1 answer:

11Alexandr11 [23.1K]3 years ago

4 0

The correct answer is 1.5 as a decimal, for a fraction it is 1 cup and a half cup. Hope this helps!!

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like terms -5b2 considered like to 5b2 or because of the negative they would be unlike or is it the b2 that makes them like?

Alexandra [31]

-5b2 is still considered to be like 5b2 because they share terms (the variable)
so it is the b that makes them alike the exponent and the negatives dont matter

7 0

4 years ago

AP CAL AB HELP!

Paul [167]

Answer:

$\frac{dc}{dt}\approx13.8146\text{ km/min}$

Step-by-step explanation:

We know that the plane travels at a <em>constant</em> speed of 14 km/min.

It passes over a radar station at a altitude of 11 km and climbs at an angle of 25°.

We want to find the rate at which the distance from the plane to the radar station is increasing 4 minutes later. In other words, if you will please refer to the figure, we want to find dc/dt.

First, let's find c, the distance. We can use the law of cosines:

$c^2=a^2+b^2-2ab\cos(C)$

We know that the plane travels at a constant rate of 14 km/min. So, after 4 minutes, the plane would've traveled 14(4) or 56 km So, a is 56, b is a constant 11. C is 90+20 or 115°. Substitute:

$c^2=(56)^2+(11)^2-2(56)(11)\cos(115)$

Evaluate:

$c^2=3257-1232\cos(115)$

Take the square root of both sides:

$c=\sqrt{3257-1232\cos(115)}$

Now, let's return to our law of cosines. We have:

$c^2=a^2+b^2-2ab\cos(C)$

We want to find dc/dt. So, let's take the derivative of both sides with respect to t:

$\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2+b^2-2ab\cos(C)]$

Since our b is constant at 11 km, we can substitute this in:

$\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2-(11)^2-2a(11)\cos(C)]$

Evaluate:

$\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2-121-22a\cos(C)]$

Implicitly differentiate:

$2c\frac{dc}{dt}=2a\frac{da}{dt}-22\cos(115)\frac{da}{dt}$

Divide both sides by 2c:

$\frac{dc}{dt}=\frac{2a\frac{da}{dt}-22\cos(115)\frac{da}{dt}}{2c}$

Solve for dc/dt. We already know that da/dt is 14 km/min. a is 56. We also know c. Substitute in these values:

$\frac{dc}{dt}=\frac{2(56)(14)-22\cos(115)(14)}{2\sqrt{3257-1232\cos(115)}}$

Simplify:

$\frac{dc}{dt}=\frac{1568-308\cos(115)}{2\sqrt{3257-1232\cos(115)}}$

Use a calculator. So:

$\frac{dc}{dt}\approx13.8146\text{ km/min}$

And we're done!

6 0

3 years ago

Shelley's cup of tea cooled down 1/2 of a degree in 10 minutes. At what rate is her tea cooling down?

Vlada [557]

Answer:

0.05 degrees a minute

Step-by-step explanation:

1/2 a degree divided by 10 is 0.05 degrees a minute

3 0

3 years ago

15 Points Help Math question

gizmo_the_mogwai [7]

11.11111111

you can round your answer

divide 27 by 9 you get 3

divide hundred by 9
you get your answer

3 0

3 years ago

Choose all the zeros of the quadratic function defined by the expression 2x2 + 5x - 12

Andrej [43]

Answer:

3/2 and -4

Step-by-step explanation:

that is the answer

8 0

3 years ago