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Fofino [41]
3 years ago
12

Priya volunteers at her local library 5 days each week. The round-trip distance from her home to the library is 0.87 miles. How

many miles does Priya travel each week to and from the library? How can you find the answer to the problem? Check all that apply.
Mathematics
2 answers:
bagirrra123 [75]3 years ago
7 0

Answer:

Priya Just Priya

Step-by-step explanation:

MATH Bro

Sphinxa [80]3 years ago
6 0

Answer:

"Starting today, I need to forget what's gone. Appreciate what still remains and look forward to what's coming next."

"Pain makes you stronger, fear makes you braver, heartbreak makes you wiser."

"I will not allow myself to not feel chosen every single day. And I’ll wait till whenever that is." — Hannah Brown

"Sometimes good things fall apart so better things can come together."

"Live for what today has to offer, not for what yesterday has taken away."

"Accept what is, let go of what was, and have faith in what will be."

"Don't be afraid to start over. It’s a brand new opportunity to rebuild what you truly want."

"Inhale the future, exhale the past."

"Don’t cry because it’s over, smile because it happened."

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Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
Suppose the first term of a geometric sequence is 3 and the fourth term is 192. What is the common ratio of the sequence? Write
gayaneshka [121]
An=A1 r ^(n-1)
192= 3 r ^(4-1)
192 = 3 r^3
64 = r^3
r = 4

equation:
An=3 (4)^(n-1)

6th term:
An= 3 (4)^(6-1)
An= 3072

I think this is right :)
3 0
3 years ago
If the price of a car decreases by 12%, the price would be 26,880. What is the original price
melomori [17]

Answer:

26,880/12%=224000

Step-by-step explanation:

4 0
3 years ago
Evaluate the composition of functions.
valina [46]

Answer:

  2

Step-by-step explanation:

Fill in each function's argument and do the arithmetic.

  h(g(f(\sqrt{10})))=h(g(2(\sqrt{10})^2-7))=h(g(2\cdot 10-7))=h(g(13))\\\\=h(\dfrac{4-13}{9})=h(\dfrac{-9}{9})=h(-1)\\\\=\sqrt{-(-1)+3}=\sqrt{4}=\boxed{2}

7 0
2 years ago
Work out the value of 5x8 x 5-2/5x4
Alisiya [41]

Answer:

=6

Step-by-step explanation:

(5×8)×(5-2)/(5×4)

Numerator =40×3

=120

Denominator = 5×4

=20

simplifying 120/20

=6

5 0
3 years ago
Read 2 more answers
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