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Levart [38]
3 years ago
8

A friend tells you that she has conducted a survey to find the proportion of people in her university that utilize the campus in

ternet cafe at least once a day. She has collected a sample and calculated a sample proportion of p = 0.68. She uses this value to calculate a confidence interval for the population proportion. Your friend says that she is not going to tell you the sample size or the level of confidence used in her construction, and wants you to guess what the confidence interval is. She gives you 5 options.
Select the interval(s) that, based on the information given, could possibly be the confidence interval your friend calculated:

a. the interval between 0.68 and 0.88
b. the interval between 0.58 and 0.78
c. the interval between 0.48 and 0.78
d. the interval between 0.58 and 0.88
e. the interval between 0.48 and 0.68
Mathematics
2 answers:
o-na [289]3 years ago
4 0

Answer:

The anser is d

Step-by-step explanation:

gogolik [260]3 years ago
3 0
The right answer for this question is D
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Solve for a.<br><br> 5a - 2 = 23
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Please Help! Multiple Choice!
Katyanochek1 [597]

Using the z-distribution, the p-value would be given as follows:

b) 0.0086.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis we test if the means are equal, hence:

H_0: \mu_D - \mu_C = 0

At the alternative hypothesis, it is tested if they are different, hence:

H_1: \mu_D - \mu_C \neq 0

<h3>What are the mean and the standard error for the distribution of differences?</h3>

For each sample, they are given as follows:

  • \mu_D = 12, s_D = \frac{5.2}{\sqrt{73}} = 0.6086
  • \mu_C = 14, s_C = \frac{4.1}{\sqrt{81}} = 0.4556

Hence, for the distribution of differences, they are given by:

  • \overline{x} = 12 - 14 = -2.
  • s = \sqrt{0.6086^2 + 0.4556^2} = 0.76

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

z = \frac{\overline{x} - \mu}{s}

z = \frac{-2 - 0}{0.76}

z = -2.63.

Using a z-distribution calculator, for a two-tailed test, with z = -2.63, the p-value is of 0.0086.

Hence option B is correct.

More can be learned about the z-distribution at brainly.com/question/13873630

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