Answer:
See Below
Step-by-step explanation
1) subtract 4 from both sides
You have the answer
We are given two points: (4, -8) and (8, 5)
General equation of a line: y = mx + c
First find m (the gradient). There is a formula for this: (change in y)/(change in x) = gradient
(5 - -8) / (8 - 4) = (13) / (4) = 3.25 = m
y = 3.25x + c
Now we need to find c (the y-intercept; the value of y when x=0).
Substitute in any one of the coordinates - let's use (8, 5)
(5) = 3.25(8) + c
(5) = 26 + c
c = -21
The equation of the line: y = 3.25x - 21
I think that this answer is correct - sorry if it seems rushed.
Hope this answer helps :)
All the triangles are similar, so the ratio of (long leg)/(short leg) is the same. The long leg of ΔADB is
.. AD = AC -DC = 20 -4
.. AD = 16
Then
.. (long leg)/(short leg) = AD/DB = BD/DC
.. 16/h = h/4
.. h^2 = 64
.. h = 8
Selection D is appropriate.
_____
You may see this again. The altitude (h) from the right angle in a right triangle is the geometric mean of segments AD and DC. That is,
.. h = √((AD)*(DC))
Answer:
74.86% probability that a component is at least 12 centimeters long.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Variance is 9.
The standard deviation is the square root of the variance.
So

Calculate the probability that a component is at least 12 centimeters long.
This is 1 subtracted by the pvalue of Z when X = 12. So



has a pvalue of 0.2514.
1-0.2514 = 0.7486
74.86% probability that a component is at least 12 centimeters long.