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Elan Coil [88]
3 years ago
7

A unit rate is a rate with a

Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0

Answer:

A unit rate is one in which the numerator of the fraction is compared to a denominator of one unit.

Step-by-step explanation:

hope that works

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Select the correct answer.
Rashid [163]

Answer: D. (4,3)

The x coordinates of A and B are 9 and -1 in that order. Add them up to get 9+(-1) = 9-1 = 8. Then divide by two to end up with 8/2 = 4. The midpoint has an x coordinate of 4.

Repeat for the y coordinates. Add them up: 8+(-2) = 8-2 = 6. Then divide by two: 6/2 = 3. The midpoint has an y coordinate of 3.

Those two coordinates pair up to get (x,y) = (4,3) which is the midpoint of segment AB.

7 0
3 years ago
Help plsssss I will mark as brainlest if correct
Gennadij [26K]

Replace x with a couple of numbers, solve for Y them mark those points on the graph and connect with a line.

See picture:

5 0
3 years ago
Please help me understand more about it so I can do it myself! So it’s about proportions. The problem is x/7 = 6/8
sasho [114]

Answer: 5¼

Step-by-step explanation:

x/7 = 6/8

8x = 42

x = 5¼

7 0
4 years ago
Show all steps!!!
Lunna [17]
-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3
\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12}
\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}
=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}
=-\frac{53}{6}
4 0
4 years ago
HELP QUICK!
makvit [3.9K]

Using the function concept, it is found that f is a function, as each student is related to only one GPA and only one number of credits.

In a function, <u>one value of the input can be related to only one value of the output</u>.

In this problem:

  • The input is the student.
  • The output is the student GPA, and the number of credits earned.

Each student is related to only one GPA and only one number of credits, hence <u>one value of the input is related to only one value of the output</u>, and f is a function.

To learn more about the function concept, you can take a look at brainly.com/question/12463448

8 0
3 years ago
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