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netineya [11]
3 years ago
11

A plane is flying at 31,348 feet. It needs to rise to 37,000 feet in two stages. In stage 1, it rises 5% of its

Mathematics
2 answers:
TEA [102]3 years ago
7 0
The Answer is 22 Minutes

son4ous [18]3 years ago
6 0

Answer:

The plane needs 29.1 minutes to rise during stage 2.

Step-by-step explanation:

Initially, the plane is flying at 31348 ft. It needs to rise to 37000 ft in two stages (S2).

The first stage (F), it rises 5%(P) of its initial altitude of 31348 ft (I).

F = (I*P)

F = (31348 ft* (5/100))=1567.4 ft

5% represents 1567.4 ft. It means, total alttitude for fist stage (T1) is F + I

T1 = F+I

T1 = 1567.4+31348 = 32915.4 ft

Second stage (S) it raises at a rate (R) of 140.3 ft/min. We need to calcualte the altitude for second stage, as the difference of S2 and T1.

S = S2 - T1

S = 37000 ft - 32915.4 ft

S = 4084.6 ft

S is the altitude required during the second stage with a rate R of 140.3 ft/min. We need to calculate the time (t), we can do it dividing S by R.

t = S/Rt = (4084.6 ft)/(140.3 ft/min)

t = 29.1 min

Finally, The plane needs 29.1 minutes to rise during stage 2. 

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USPshnik [31]

Answer:

Step-by-step explanation:

Hello!

There are 4 3D printers available to print drone parts, then be "Di" the event that the printer i printed the drone part (∀ i= 1,2,3,4), and the probability of a randomly selected par being print by one of them is:

D1 ⇒ P(D1)= 0.15

D2 ⇒ P(D2)= 0.25

D3 ⇒ P(D3)= 0.40

D4 ⇒ P(D4)= 0.20

Additionally, there is a chance that these printers will print defective parts. Be "Ei" represent the error rate of each print (∀ i= 1,2,3,4) then:

P(E1)= 0.01

P(E2)= 0.02

P(E3)= 0.01

P(E4)= 0.02

Ei is then the event that "the piece was printed by Di" and "the piece is defective".

You need to determine the probability of randomly selecting a defective part printed by each one of these printers, i.e. you need to find the probability of the part being printed by the i printer given that is defective, symbolically: P(DiIE)

Where "E" represents the event "the piece is defective" and its probability represents the total error rate of the production line:

P(E)= P(E1)+P(E2)+P(E3)+P(E4)= 0.01+0.02+0.01+0.02= 0.06

This is a conditional probability and you can calculate it as:

P(A/B)= \frac{P(AnB)}{P(B)}

To reach the asked probability, first, you need to calculate the probability of the intersection between the two events, that is, the probability of the piece being printed by the Di printer and being defective Ei.

P(D1∩E)= P(E1)= 0.01

P(D2∩E)= P(E2)= 0.02

P(D3∩E)= P(E3)= 0.01

P(D4∩E)= P(E4)= 0.02

Now you can calculate the probability of the piece bein printed by each printer given that it is defective:

P(D1/E)= \frac{P(E1)}{P(E)} = \frac{0.01}{0.06}= 0.17

P(D2/E)= \frac{P(E2)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D3/E)= \frac{P(E3)}{P(E)} = \frac{0.01}{0.06}= 0.17

P(D4/E)= \frac{P(E4)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D2)= 0.25 and P(D2/E)= 0.33 ⇒ The prior probability of D2 is smaller than the posterior probability.

The fact that P(D2) ≠ P(D2/E) means that both events are nor independent and the occurrence of the piece bein defective modifies the probability of it being printed by the second printer (D2)

I hope this helps!

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DanielleElmas [232]
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hichkok12 [17]

Answer:

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Step-by-step explanation:

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Dennis_Churaev [7]

Answer: True

Step-by-step explanation: This is because they are equivalent fractions

Hope this helps and have a nice day

4 0
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DochEvi [55]

Step-by-step explanation:

We just have to remember the line equation <u>y=mx+b</u> , then place the given equation into this form (y= -3x-6).

Remember that (m) is your slope. So, to find a parallel line, they must have an equal slope. Check the other equations and see which one had a slope of -3. The answer C also has a slope of -3. So those lines would be parallel.

6 0
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