Please help me, it’s very important

inn [45]

Answer:

A) not similar

Step-by-step explanation:

for the triangles to be similar the side lengths must be proportional.

For example:

99/35 should be equal to 121/44 but when we do cross multiplying we see they are not equal therefore the the triangles are not similar.

5 0

2 years ago

Someone please help me on this question

Rudik [331]

$100 + 10x=15x$ . Subtract 10x from both sides. $100=5x$ . Divide by 5 on both sides. x=20. So you would need to buy 20 movies.

7 0

2 years ago

What is the average velocity between 12.00 and 15.00 seconds

bekas [8.4K]

The average between 12.00 and 15.00 seconds
can be defined in a few different ways.

Way #1: (speed)

   Average speed =
   (1/2) (the speed at 12 seconds + the speed at 15 seconds) .

Way #2: (speed)

   Average speed =
   (1/3) (the distance covered between 12.00 and 15.00 seconds)

Way #3: (velocity)

   Average velocity =
   (1/3) (distance between location at 12 sec and location at 15 sec)
   in the direction from location at 12 sec to location at 15 sec.

That's the best we can do with the combination of given and
not given information in the question.

3 0

3 years ago

Read 2 more answers

Solve for T in P=IRT

cestrela7 [59]

divide by I and r so t=p/(ir)

4 0

2 years ago

Read 2 more answers

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for <em>h: </em>

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

2 years ago