Answer:
<em>B.) 440</em>
Explanation:
I added everything together.
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Information Given
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Total Cost of the stamps = $9.00 - $1.75 = $7.25
Total number of stamps = 60
Value of the $0.10 stamp = $0.10
Value of the $0.15 stamp = $0.15
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Assumed all $0.10 stamps.
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Assumed all the 60 stamps she bought were $0.10 stamps.
$0.10 x 60 = $6.00
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Find amount not accounted for.
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Amount of money not accounted for:
$7.25 - $6.00 = $1.25
The $1.25 must had been used to pay for the $0.15 stamps.
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Find difference in values between the two stamps.
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Difference in the value of the two stamps:
$0.15 - $0.10 = $0.05
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Find number of $0.15 stamps
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Number of $0.15 stamps = $1.25 ÷ $0.05 = 25
There were 25 $0.15 stamps.
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Find number of $0.10 stamps.
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Number of $0.10 stamps = 60 - 25 = 35
There were 35 $0.10 stamps.
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Answer: 35 $0.10 stamps and 25 $0.10 stamps.
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The answer is NO,because if you put 3 CDs or less in each shelf you only can put 15 (3*5=15), the same reason for both questions.
Answer:
See below.
Step-by-step explanation:
I would use cot x = cos x / sin x:
csc x sec x cot x
= csc x * 1/cos x * cos x / sin x
The cos x disappears:
= csc x * 1 / sin x
= csc^2 x.
A. -6+2y
Step-by-step explanation:
-2×3-2×(-y)
multiply the numbers
-6-2×(-y)
multiplying two negatives equals a positive
-6+2y