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weeeeeb [17]
3 years ago
12

what is the value of the expression? 4(6/10−1/5)+0.4 enter your answer, in simplest form, in the box.

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer: 2.0

Step-by-step explanation:

The given expression : 4(\dfrac{6}{10}-\dfrac{1}{5})+0.4

To solve the given expression , we need to follow BODMAS (Bracket→ Of Divide→ Multiplication →Add →Subtract).

According to BODMAS , first we simplified the expression present inside the brackets .

4(\dfrac{6-2(1)}{10})+0.4  [10= LCM[10,5]]

=4(\dfrac{6-2}{10})+0.4

=4(\dfrac{4}{10})+0.4

=(\dfrac{4\times4}{10})+0.4   [Multiply]

=(\dfrac{16}{10})+0.4   [Simplify]

=1.6+0.4=2.0 [Add]

Hence, the value of the expression in the simplified form = 2.0

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What is the area of a rectangle with a length of (x - 5) and width of (x + 8)?
dlinn [17]

Answer:

a = x² + 3x - 40

Step-by-step explanation:

a = l * w

a = (x - 5)(x + 8)

a = x(x + 8) - 5(x + 8)

a = (x² + 8x) + (- 5x - 40)

a = x² + 3x - 40

3 0
3 years ago
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A survey results of a middle school shows that 3/20 of the students played football. what percentage of the students play footba
joja [24]

Answer: 15%

Step-by-step explanation:

From the question, we are informed that a survey results of a middle school shows that 3/20 of the students played football.

The percentage of the students that play football in this schools would be calculated as multiplying the fraction by 100. This will be:

= 3/20 × 100

= 3 × 5

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8 0
3 years ago
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4 0
1 year ago
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Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac
melomori [17]
Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ b+c=20
Equation [2] ⇒ 1.50b+5c=54.50

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; b and c, that we need to solve, then this becomes a simultaneous equation problem. 

First, rearrange Equation [1] to make either b or c the subject:
b+c=20
b=20-c

Then we substitute b=20-c into Equation [2]
1.50b+5c=54.50
1.50(20-c)+5c=54.50
30-1.50c+5c=54.50
5c-1.5c=54.50-30
3.5c=24.50
c=7

Now we know the value of c which is c=7, substitute this value into b=20-c we have b=20-7=13

Answer:
Numbers of books = 13
Numbers of CDs = 7
5 0
3 years ago
Consider the following proposed proof by contradiction that for all positive integers n, 3n > 2.
laila [671]

Answer:

The proof contains a simple direct proof, wrapped inside the unnecessary logical packaging of a proof by contradiction framework.

Step-by-step explanation:

The proof is rigourous and well written, so we discard the second answer.

This is not a fake proof by contradiction: it does not have any logical fallacies (circular arguments) or additional assumptions, like, for example, the "proof" of "All the horses are the same color". It is factually correct, but it can be rewritten as a direct proof.

A meaningful proof by contradiction depends strongly on the assumption that the statement to prove is false. In this argument, we only this assumption once, thus it is innecessary. Other proofs by contradiction, like the proof of "The square root of 2 is irrational" or Euclid's proof of the infinitude of primes, develop a longer argument based on the new assumption, but this proof doesn't.

To rewrite this without the superfluous framework, erase the parts "Suppose that the statement is false" and "The fact that the statement is true contradicts the assumption that the statement is false. Thus, the assumption that the statement was false must have been false. Thus, the statement is true."

7 0
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