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Talja [164]
3 years ago
8

In one year, a government collected about $6250 per person in taxes. If the population was 270,000,000, how much did the governm

ent collect in taxes that year?
Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0

Answer:

1,687,500,000,000

Step-by-step explanation:

1) 270,000,000 x 6250

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4x/5 - 3x/7 = 4x/7 + 5x/7 can anyone please help with explanation...​
kirill115 [55]

Answer: x=0

Step-by-step explanation:

Multiply both sides of the equation by 35, the least common multiple of 5,7.

7×4x−5×3x=5×4x+5×5x

Multiply 7 and 4 to get 28.

28x−5×3x=5×4x+5×5x

Multiply −5 and 3 to get −15.

28x−15x=5×4x+5×5x

Combine 28x and −15x to get 13x.

13x=20x+25x

Combine 20x and 25x to get 45x.

13x=45x

Subtract 45x from both sides

13x−45x=0

Combine 13x and −45x to get −32x

−32x=0

Product of two numbers is equal to 0 if at least one of them is 0. Since −32 is not equal to 0, x must be equal to 0.

X=0

7 0
3 years ago
What is the value of x if e3x+6=8
jarptica [38.1K]

Answer:

x=ln(2)/3

Step-by-step explanation:

e^3x+6=8

e^3x=8-6

e^3x=2

ln(e^3x)=ln(2)

3x=ln(2)

x=ln(2)/3

3 0
3 years ago
What is the value of the expression (2)^6?<br>pls help ​
Ronch [10]

Answer:

64

Step-by-step explanation:

2^6, or 2⁶, is two to the power of six.

Basically you multiply the bottom number (in this case 2) by itself as many times as the the number in the top right (in this case six)

2^6=2*2*2*2*2*2=64

8 0
3 years ago
Read 2 more answers
If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,
julsineya [31]
<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

<h2>Why?</h2>

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)

(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0
3 years ago
A store has a 40%, percent off sale on headphones. With this discount, the price of one pair of headphones is 36$.
mariarad [96]
$90 because you take the discounted price then divide it by .40 (40%)
3 0
3 years ago
Read 2 more answers
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