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Alla [95]
3 years ago
5

HELP!!!!

Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0

Answer:

(10+2p)/p=((20+0.80p)/p)+1

Step-by-step explanation:

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In a chest there are some gold coins. Captain takes half the coins. Sally takes a quarter of the coins. There are 3 coins left.
amid [387]

Answer:

<u>There were 12 gold coins in the chest at the start.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

x = Number of gold coins in a chest

1/2x = Number of gold coins taken by the captain

1/4x = Number of gold coins taken by Sally

3 = Number of gold coins left

2. How many coins were in the chest at the start?

Let's write the following equation to solve for x:

1/2x + 1/4x + 3 = x

2x + x + 12 = 4x (Lowest Common Denominator is 4)

4x - 2x - x = 12 (Like terms)

x = 12

<u>There were 12 gold coins in the chest at the start.</u>

3 0
4 years ago
4-2(3+2) ²<br> 2.<br> Help me plz i need the help
strojnjashka [21]

Answer:

-46 is your answer.

Step-by-step explanation:

=4-2(3+2)^2

=4-2(5)^2

=4-2(5✖️5)

=4-2(25)

Opening brackets to simplify

=4-50

=-46 is your answer.

Hope it will help you :)

5 0
3 years ago
Read 2 more answers
The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
Anettt [7]

Answer:

1) The size of the colony after 4 ​days is 6553 mosquitoes

2) After t = 4.9\ days

Step-by-step explanation:

To answer this question you must use the growth formula

N = N_0e ^ {kt}

Where

N_0 is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and N_0=1000 then N = 1600

Then we use these values to find k.

1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47

Now that we know k we can find the size of the colony after 4 days.

N = 1000e ^ {0.47(4)}\\\\N = 6553\ mosquitoes

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

10000 = 1000e ^ {0.47t}\\\\10 = e ^ {0.47t}\\\\ln(10) = 0.47t\\\\t = \frac{ln(10)}{0.47}\\\\t = 4.9\ days

6 0
3 years ago
3&lt;6c+13&lt;5 (Enter your answer in INTERVAL notation, using U to indicate a union of intervals; or enter DNE if no solution e
laiz [17]

Answer:

  (-5/3, -4/3)

Step-by-step explanation:

  3 < 6c +13 < 5 . . . . given

  -10 < 6c < -8 . . . . . subtract 13

  -10/6 < c < -8/6 . . . divide by 6

We can express the interval using reduced fractions as ...

  (-5/3, -4/3)

8 0
4 years ago
Evaluate −x^2−5 y^3 when x = 4 and y = 1
Natali [406]

Answer:

Simplify:

-4^2-5(1^3)

So you get:

-21\\

4 0
3 years ago
Read 2 more answers
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