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3 years ago

Help me please teachers trying to give me 8th grade problems

Mathematics

2 answers:

Bezzdna [24]3 years ago

5 0

Answer:

x = 2

Step-by-step explanation:

Used a scientific calculator.

murzikaleks [220]3 years ago

3 0

Answer:

x = 2

Step-by-step explanation:

5x - 7 = 3

Add seven to the minus 7 and 3

Which gives you:

5x = 10

Divide both sides by 5

Which gives you:

X = 2

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Which number is closest to 66 (squared)? A) 8.8 B) 8.1 C 8.2 D) 9.1

Hoochie [10]

Answer:

sq rt of 66 is 8.12 so 8.1 closest

8 0

3 years ago

Read 2 more answers

STVU is an isosceles trapezoid. If SV = 6x - 5 and TU = 2x + 7, find the value of x. x=3

Thepotemich [5.8K]

Because STVU is an isosceles trapezoid
so SV = TU
6x - 5 = 2x + 7
6x - 2x = 7 + 5
4x = 12
x = 3

answer
x = 3

7 0

3 years ago

HELPPPPP PLEASEEEEE!!!

Pepsi [2]

Answer:

The height of right circular cone is h = 15.416 cm

Step-by-step explanation:

The formula used to calculate lateral surface area of right circular cone is: $s=\pi r\sqrt{r^2+h^2}$

where r is radius and h is height.

We are given:

Lateral surface area s = 236.64 cm²

Radius r = 4.75 cm

We need to find height of right circular cone.

Putting values in the formula and finding height:

$s=\pi r\sqrt{r^2+h^2}\\236.64=3.14(4.75)\sqrt{(3.75)^2+h^2} \\236.64=14.915\sqrt{(3.75)^2+h^2} \\\frac{236.64}{14.915}=\sqrt{14.0625+h^2} \\15.866=\sqrt{14.0625+h^2} \\Switching\:sides\:\\\sqrt{14.0625+h^2} =15.866\\Taking\:square\:on\:both\:sides\\(\sqrt{14.0625+h^2})^2 =(15.866)^2\\14.0625+h^2=251.729\\h^2=251.729-14.0625\\h^2=237.6665\\Taking\:square\:root\:on\:both\:sides\\\sqrt{h^2}=\sqrt{237.6665} \\h=15.416$

So, the height of right circular cone is h = 15.416 cm

4 0

2 years ago

Evaluate the expression when a=4 b =−5 and c=−8 a+b=

stich3 [128]

The value of the expression for the given values of a and b is -1

<h3>Evaluating an expression</h3>

From the question, we are to evaluate the given expression for the given values of a, b, and c

The given expression is

a + b

The given values are

a = 4,

b = -5,

and

c = -8

To evaluate the given expression for the given values of a and b, we will put the values of a and b into the expression,

That is,

a + b becomes

4 + -5

= 4 -5

= -1

Hence, the value of the expression for the given values of a and b is -1

Learn more on Evaluating an expression here: brainly.com/question/17425636

#SPJ1

7 0

1 year ago

Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-

Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

$\sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0

3 years ago