Answer: James Watson and Francis Crick
Explanation:
In 1953 James Watson and Francis Crick are responsible for determining the structure of DNA. James and Watson proposed that the DNA is made up of a double polynucleotide chains that are twisted around each other to forming a helical structure. The two DNA chains runs anti-parallel in opposite direction to each other. Like the structure of the ladder.
The answer is James Watson and Francis Crick
The question that Charles Darwin would be prompted to ask on his voyage is as follows: can selection in nature also lead to a new species over time?.
<h3>Who is Charles Darwin?</h3>
Charles Darwin was a British naturalist/scientist and founder of the theory of evolution by natural selection.
He is best known for his award-winning work on the origin of species, which he published in 1859. Darwin developed his theory from findings he made following a five-year expedition on board HMS Beagle.
According to this question, Darwin reviewed his observations after he returned home from his voyage studying the selective breeding of pigeons.
The question that Charles Darwin would be prompted to ask on his voyage is as follows: can selection in nature also lead to a new species over time?.
Learn more about Charles Darwin at: brainly.com/question/16489282
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Answer:
d is zero (0)
Explanation:
ψ(x)=ce^κx+de^−κx
Let say x = - 1000
We have something like
ce^κ* -1000 = approximately zero
Where we assume k to be 1
C becomes zero as it tend to negative infinity
But
If k is 1
de^−1* 1000 =d * 2 * 10^434
To have a zero function d = 0
So 0 * 2 * 10^434 = 0
Drawn bow because the flexing of the bow and the increased tension in the bow string contain the energy expended by the archer’s muscles transferred to the bow. The energy is transmitted to the arrow when then it’s released. All this is mechanical energy.
The other items in the list have potential electrical energy (battery), locked energy in the nutrients released during digestion (bun), electromagnetic energy (sun).
Answer:
In order to find average speed during each interval, we need to divide the distance during those intervals with the period of time. So, for the first interval (day 0 to day 2) hawksbill started from 0 and reached 10 kilometers by the end of the second day. That means that it crossed 10 kilometers in 2 days, so the average speed is 10/2 which is 5 km/day. Similarly, we can calculate speed for other intervals:
• day 2 - day 3: it went from 10 to 12 km in one day, which means it crossed 2 km in one day, so the average speed is 2/1 = 2 km/day
• day 3 - day 4: at the end of the third day it reached 12 km and at the end of the day 4 it remained at 12 km. That means the hawksbill wasn't moving in that interval so the speed was 0
• day 4 - day 5: it went from 12 km to 18 km, which means it crossed 18-12=6 km in one day, so the average speed is 6/1=6 km/day
• day 5 - day 6: it went from 18 to 24 km, which means it crossed 24-18=6 km in one day, so the speed was 6/1=6 km/day
So, to summarize, during the first interval turtle was moving with average speed of 5 km/day, then 2 km/day, in the third interval it wasn't moving and in the last two intervals, it moved in average speed of 6 km/day.