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3 years ago

Name three ways you can solve a system of nonlinear equations.

Mathematics

1 answer:

Ann [662]3 years ago

4 0

Substitution.

Elimination.

Using a Combination of methods.

Using absolute value

I hope this helps!

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An arcade booth at a county fair has a person pick a coin from two possible coins available and then toss it. If the coin chosen

nydimaria [60]

Answer:

Step-by-step explanation:

<u>Conditional Probability</u>

Suppose two events A and B are not independent, i.e. they can occur simultaneously. It means there is a space where the intersection of A and B is not empty:

$P(A\cap B) \neq 0$

If we already know event B has occurred, we can compute the probability that event A has also occurred with the conditional probability formula

$\displaystyle P(A|B)=\frac{P(A\cap B)}{P(B)}$

Now analyze the situation presented in the question. Let's call F to the fair coin with 50%-50% probability to get heads-tails, and U to the unfair coin with 32%-68% to get heads-tails respectively.

Since the probability to pick either coin is one half each, we have

$P(U)=P(F)=50\%=0.5$

If we had picked the fair coin, the probability of getting heads is 0.5 also, so

$P(F\cap H)=0.5\cdot 0.5=0.25$

If we had picked the unfair coin, the probability of getting heads is 0.32, so

$P(U\cap H)=0.32\cdot 0.5=0.16$

Being A the event of choosing the fair coin, and B the event of getting heads, then

$P(B)=P(F\cap H)+P(U\cap H)=0.25+0.16=0.41$

$P(A\cap B)=P(F\cap H)=0.25$

$\displaystyle P(A|B)=\frac{0.25}{0.41}=0.61$

The closest answer is

b. 0.6024

7 0

3 years ago

Clara simplifies (8b

xeze [42]

Answer:

8b estaSIMPLIFIC ADA

Step-by-step explanation:

5 0

2 years ago

The scheduled arrival time for a daily flight from Boston to New York is 9:35 am. Historical data show that the arrival time fol

Lady_Fox [76]

Answer:

The mean is 11.5 minutes and the standard deviation is of 6.64 minutes

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean is:

$M = \frac{a+b}{2}$

The standard deviation is:

$S = \sqrt{\frac{(b-a)^{2}}{12}}$

Arrival time of 9:18 am and a late arrival time of 9:41 am.

9:41 is 23 minutes from 9:18. So the time is uniformily distributed between 0 and 23 minutes, so a = 0, b = 23.

Mean:

$M = \frac{a+b}{2} = \frac{0+23}{2} = 11.5$

Standard deviation:

$S = \sqrt{\frac{(b-a)^{2}}{12}} = \sqrt{\frac{(23 - 0)^{2}}{12}} = 6.64$

The mean is 11.5 minutes and the standard deviation is of 6.64 minutes

8 0

2 years ago

The graph of g(x) is a transformation of the graph of f(x)=2x. Enter the equation for g(x) in the box. g(x) =

Lunna [17]

<h3>Answer: $g(x) = 2^x - 3$ </h3>

The -3 is not in the exponent

Explanation:

The parent function is $f(x) = 2^x$ . Plugging in x = 0 leads to y = 1. So the point (0,1) is on the f(x) curve. Going from (0,1) to (0,-2) is a vertical shift of 3 units downward. To represent this shift, we tack on a "-3" at the end of the f(x) function.