Answer:
A) JK and LM will be parallel to each other.
Step-by-step explanation:
On reflection on
line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

Points on line EF

On reflection of this line on
the new points we get for line JK are

Points on line GH

On reflection on y=x line the new points we get for line LM are

Slope of line JK

Slope of line LM

For two line to be parallel, their slopes will be same.

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.
See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
Answer:
the third one
Step-by-step explanation:
x^2 is always non-negative, so -3x^2 will always be non-positive. You can eliminate any tables with positive values for y.
<h3>
Answer: 580 square cm</h3>
===================================================
Work Shown:
A = area of smaller rectangle
A = length*width
A = 35*22
A = 770
B = area of larger rectangle
B = length*width
B = 45*30
B = 1350
C = area of the border only
C = B - A
C = 1350-770
C = 580 square cm
Answer:
Rn-222
Step-by-step explanation:
this decay takes specified step therefore Rn-222is not a decaying process