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enot [183]
3 years ago
11

What are the common factors for 88 and 24

Mathematics
1 answer:
Zinaida [17]3 years ago
7 0
To find the common factors between two numbers, you must first break the numbers down into factors, and then find all common factors.
Let's break down 88.

88: 2 x 44, 4 x 22, 8 x 11.

Now let's break down 24.

24: 2 x 12, 3 x 8, 4 x 6.

Now that we've factored both numbers, let's select all the common factors.

Common factors:
1, 2, 4, 8.

I hope this helps!
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What is a constant term or variable term that makes 5x + 20 = 5x + ? have one solution?
In-s [12.5K]

Answer:

It would be 20

Step-by-step explanation:

because 5x+20 = 5x + <u>         </u>

it would have to be 20

to have 1 solution

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What is the range of the function y=3x-2 if the domain is {0,1,2}
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6. Find an exact value. (1 point)
vladimir2022 [97]
<span>6 Find an exact value. 
sin 75°
</span>sin(A+B)=sin(A)cos(B)+cos(A)sin<span>(B)
</span>sin(45)=cos(45)=(2^0.5)/2    sin(30)=0.5      cos(30)=(3^0.5)/2
sin(45+30)=sin(45)cos(30)+cos(45)sin(30)=(6^0.5+2^0.5)/4
the answer is the letter d) quantity square root of six plus square root of two divided by four.

<span>7. Find an exact value. 
sine of negative eleven pi divided by twelve.

</span>sin(-11pi/12) = -sin(11pi/12) = -sin(pi - pi/12) = -sin(pi/12) = -sin( (pi/6) / 2)

= - sqrt( (1-cos(pi/6) ) / 2) = -sqrt( (1-√3/2) / 2 ) = -(√3-1) / 2√2=(√2-√6)/4
the answer is the letter c) quantity square root of two minus square root of six divided by four.

<span>8. Write the expression as the sine, cosine, or tangent of an angle. 
sin 9x cos x - cos 9x sin x
</span>

sin(A−B)=sinAcosB−cosAsinB

sin(9x−x)= sin9xcosx−cos9xsinx= sin(8x)

the answer is the letter c) sin 8x

<span>9. Write the expression as the sine, cosine, or tangent of an angle. 
cos 112° cos 45° + sin 112° sin 45°

</span>

cos(A−B)=cosAcosB<span>+sinA</span>sinB

cos(112−45)=cos112cos45<span>+sin112</span>sin45=cos(67)

the answer is the letter d) cos 67°

10. Rewrite with only sin x and cos x.

sin 2x - cos 2x

 

sin2x = 2sinxcosx<span>
cos2x = (cosx)^2 - (sinx)^2 = 2(cosx)^2 -1 = 1- 2(sinx)^2</span>

sin2x- cos2x=2sinxcosx-(1- 2(sinx)^2=2sinxcosx-1+2(sinx)^2

sin2x- cos2x=2sinxcosx-1+2(sinx)^2

<span>the answer is the letter <span>b) 2 sin x cos2x - 1 + 2 sin2x</span></span>
4 0
3 years ago
Read 2 more answers
Please help solve this!
algol13

Answer:

There’s nothing to solve?

Step-by-step explanation:

7 0
3 years ago
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Stuck on this question because I left my calculator and the others aren’t working please help
Pavlova-9 [17]

Answer:

-94%, -0.925, -9/10, -8/9

Step-by-step explanation:

-94% = -0.94

-8/9 = -0.89

-9/10 = -0.90

Since the values are negative the order is opposite then if they were all positive.

8 0
3 years ago
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