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3 years ago

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Square root of 512k^2. show work

2 answers:

crimeas [40]3 years ago

6 0

(I don't seem to have a raical on this thing, so this _/ will have to serve as one) you take the _/512 and the _/k^2 the squared root of k^2 is simply k. the squared root of 512, however, is not so simple. you are going to have to factor it out. so 512 factors into a bunch of numbers. we want to root it. it would be approximately 22.84732. so 22 will not be a factor. now. let's divide 512 by two. 216. now divide that by two. 108. so. we've by two how many times? we are going to want to multiply all of this up until we find a few like terms. I have found a few threes in the mix. so I have 2*2*2*2*3*3*3. so as you can see have two 12s and a three left over. so we have the under the radical _/12^2*3. twelve squared can now get out of the radial and become 12_/3. so your answer will be 12_/3 * k.

storchak [24]3 years ago

3 0

<span><span>square root of 512k^2
</span></span><span>Problem:</span><span>Simplify
<span> <span><span>512<span>k2</span> </span><span>−−−−−</span>√</span> </span>Step-By-Step Solution:Rewrite <span>512<span>k2</span></span> as <span><span><span>(<span>16k</span>)</span>2</span>⋅2</span>.More Steps<span><span><span><span>(<span>16k</span>)</span>2</span>⋅2</span><span>−−−−−−−−</span>√</span>Pull terms out from under the radical.<span><span><span>16k</span><span>2√</span></span></span></span>

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dimaraw [331]

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With the fewest terms possible is

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Solve the following quadratic equation using the quadratic formula. Which of the following expressions gives the numerators of t

Illusion [34]

I hope the choices for the numerators of the solutions are given.

I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.

The standard form of a quadratic equation is :

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So, first step is to compare the given equation with the above equation to get the value of a, b and c.

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Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

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Imagine a right angled triangle with one of its acute angle as $\theta$ .

The side opposite to this angle will be perpendicular .
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$\sf\longrightarrow sin\theta =\dfrac{p}{h} \\$

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And by Pythagoras theorem ,

$\sf\longrightarrow h^2 = p^2+b^2 \dots (i)$

Where the symbols have their usual meaning.

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From equation (i) ,

$\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\$

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Since LHS = RHS ,

Hence Proved !

I hope this helps.

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1 year ago