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Setler79 [48]
3 years ago
12

Show how to solve 8x^2+14x+5=0 by completing the square.

Mathematics
1 answer:
Phoenix [80]3 years ago
8 0
8 x² + 14 x + 5 = 0
2 ( 4 x² + 7 x ) = - 5
2 ( 4 x² + 7 x + 49/16 - 49/16 ) = -5
2 ( 4 x² + 7 x + 49/16 ) - 98/16 = - 5
2 ( 2 x + 7/4 )² = - 5 + 98/16
2 ( 2 x + 7/4 )² = -80/16 + 98/16
2 ( 2 x + 7/4 )² = 18/16 = 9/8       / : 2
( 2 x + 7/4 )² = 9/16     / √
2 x + 7/4 = 3/4
2 x = 3/4 - 7/4 = -1
x = - 1
and  2 x + 7/4 = -3/4
2 x = -7/4 - 3/4 = - 10/4= -5/2
x = - 5 / 4
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What are the greatest common divisors of these pairs of integers?a. 3⁷. 5³. 7³,2ⁱⁱ.3⁵.5⁹b. 11.13.17, 2⁹.3⁷.5⁵.7³c. 23³ⁱ,23ⁱ⁷d. 4
KatRina [158]

Answer:

a) 3⁵5³.

b) 1

c) 23³

d) 41·43·53

e) 1

f) 1111

Step-by-step explanation:

The greatest common divisor of two integers is the product of their common powers of primes with greatest exponent.

For example, to find gcd of 2⁵3⁴5⁸ and 3⁶5²7⁹ we first identify the common powers of primes, these are powers of 3 and powers of 5. The greatest power of 3 that divides both integers is 3⁴ and the greatest power if 5 that divides both integers is 5², then the gcd is 3⁴5².

a) The greatest common prime powers of 3⁷5³7³ and 2²3⁵5⁹ are 3⁵ and 5³ so their gcd is 3⁵5³.

b) 11·13·17 and 2⁹3⁷5⁵7³ have no common prime powers so their gcd is 1

c) The only greatest common power of 23³ and 23⁷ is 23³, so 23³ is the gcd.

d) The numbers 41·43·53 and 41·43·53 are equal. They both divide themselves (and the greatest divisor of a positive integer is itself) then the gcd is 41·43·53

e) 3³5⁷ and 2²7² have no common prime divisors, so their gcd is 1.

f) 0 is divisible by any integer, in particular, 1111 divides 0 (1111·0=0). Then 1111 is the gcd

5 0
3 years ago
About how much money did the forth grade students raise? Explain.
ozzi

(32x12) +(25x14)+ (18x14) + (47x12)=

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Step-by-step explanation:

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Answer: The answer is 4.

Step-by-step explanation: Given that -

The number of cups of yogurt that Carol has to make smoothies is given by

c_y=1\dfrac{5}{8}=\dfrac{13}{8},

and the number of cups of yogurt that each smoothies uses is given by

c_s=\dfrac{1}{3}.

Let 'n' be the number of smoothies that Carol can make with the available yogurt, then we have

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Thus, the maximum number of smoothies is 4.

5 0
3 years ago
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