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Novay_Z [31]
3 years ago
9

4 sin(2x) = 4 cos(x)

Mathematics
1 answer:
Virty [35]3 years ago
8 0
Its simple check symbolab.com

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A baby is born having a mass of 3,000 grams and gains 200 grams in the following week. How much does the baby weigh one week aft
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7 pounds 0.8767 ounces

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12. How many students scored at least 60 on the test?<br> a) 3<br> b) 4<br> c) 11<br> d) 7
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Brinn's rectangular kitchen has an area of 81 square feet. the kitchen is 9 times as many square feet as Brinn's pantry. If the
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Write an absolute value function that shifted 2<br> units right.<br><br> HELPPPP
iVinArrow [24]

Answer: (a)

Step-by-step explanation:

Suppose the original function is y=\left | x \right |

To shift it 2 units right, replace x by x-2 such that

\Rightarrow x-2=0\\\Rightarrow x=2

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3 years ago
A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =
tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

f(x)=-16x^2+64x+5

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

10=-16x^2+64x+5

Subtracting 10 from both sides:

-16x^2+64x-5=0

For simplicity, divide both sides by -1:

16x^2-64x+5=0

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Substitute:

\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}

Evaluate:

\displaystyle x=\frac{64\pm\sqrt{3776}}{32}

Simplify the square root:

\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}

Therefore:

\displaystyle x=\frac{64\pm8\sqrt{59}}{32}

Simplify:

\displaystyle x=\frac{8\pm\sqrt{59}}{4}

Approximate:

\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0
2 years ago
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