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4 years ago

Simply the expression 2(6+3n)-4

Mathematics

1 answer:

Ronch [10]4 years ago

3 0

Answer:

8+6n

Step-by-step explanation:

First, distribute the 2 into the parenthesis.

2(6)+2(3n)-4

Then, multiply the numbers.

12+6n-4

Now add(subtract in this case) the common multiples.

12-4= 8

8+6n

Since you can no longer simplify the equation, this is the answer..

8+6n

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Answer:

The correct option is (1).

Step-by-step explanation:

The given system of equation is,

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$y=3x+3$ .... (2)

The solution of the system of equation is the point where both line intersect each other.

Solve the equation by method of elimination.

Multiply equation 1 by 3.

$3y=-3x+12$ ... (3)

Add equation (2) and (3).

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4 years ago

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3 years ago

Susan was thinking of a number that when she multiplies it by two and then

Gnesinka [82]

Answer:

-4

Step-by-step explanation:

Let the number be x

If she multiplies the number by 2, it will become 2x

If divided by 4, it will be 2x/4, if she multiplies the result by itself, we will have:

2x/4(2x/4) = 4x/16

If she subtract the original number from 6 and divide by 10, we will have;

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Equating both expressions

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Cross multiply

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3 years ago

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stira [4]

Answer:

A(0,10)

Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

s ≥ 10 -t (2)

s ≤ 20-t (3)

s ≥ 0

t ≥ 0

Let analyse all 4 possible answer:

A(0, 10)

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

B (0, 20)

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0 True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

C. (4, 16)

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4 True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

D. (16,4)

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A(0,10) is not one of the vertices of the shaded region of the set of inequalities.

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3 years ago