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SVETLANKA909090 [29]
3 years ago
9

I have no idea how to do this. I need some help. Thanks in advance.

Mathematics
1 answer:
iris [78.8K]3 years ago
3 0

if we run a line from a corner(vertex) in a triangle, towards the middle-point of the opposite side, the line we get is called a median, so in this triangle we have three medians, AE, CD and BF.

now, since the median hits the opposite side in the middle, that means two equal halves from that middle


the line where all medians meet inside the triangle is the centroid.  The centroid cuts all medians in a 2:1 ratio, so one side of the median is twice as long as the other side.

we know CD = 18, let's split it in a 2:1 ratio

\bf 18\qquad 2:1\qquad \cfrac{2}{1}\qquad \cfrac{2\cdot \frac{18}{2+1}}{1\cdot \frac{18}{2+1}}\implies \cfrac{2\cdot 6}{1\cdot 6}\implies \cfrac{12}{6} \\\\\\ \cfrac{GC}{DG}=\cfrac{12}{6}\implies DG=6\qquad GC=12


we also know that AG = 10, and that AG : GE is a ratio of 2:1, so is AG is 10, then GE must be half that, because AG is twice as much as GE, so GE = 5, and AG + GE = AE, so AE = 15.

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Question is 15 points
Blababa [14]

sin(x+y)=sin(x)cos(y)-cos(x)sin(y)

also, remember pythagorean rule, sin^2(x)+cos^2(x)=1

given that sin(Θ)=4/5 and cos(x)=-5/13

find sin(x) and cos(Θ)


sin(x)

cos(x)=-5/13

using pythagorean identity

(sin(x))^2+(-5/13)^2=1

sin(x)=+/- 12/13

in the 2nd quadrant, sin is positve so sin(x)=12/13


cos(Θ)

sin(Θ)=4/5

using pythagrean identity

(4/5)^2+(cos(Θ))^2=1

cos(Θ)=+/-3/5

in 1st quadrant, cos is positive

cos(Θ)=3/5


so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)

sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)

sin(Θ+x)=16/65



answer is 1st option

7 0
3 years ago
Is this right ? Plz help mee
sasho [114]
6.32 is the final answer! :)
6 0
3 years ago
Read 2 more answers
A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r
eduard

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

            Radius= 1.5 m

            Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= 2\pi rh

Considering, π= 3.14

⇒ lateral surface area of cylinder= 2\times 3.14\times 1.5\times 2.5

⇒ lateral surface area of cylinder= 23.55 \ m^{2}

∴ Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= \frac{16500}{23.55} = 700.6369 \approx 701

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

8 0
3 years ago
Can someone please answer the problem in the picture?
Elenna [48]

Answer:

Rate of change is 6/7      Initial value: 6

Step-by-step explanation:

To find the slope (which is the rate of change), use (y1 - y2)/(x1 - x2).

x1 and y1 will be (0, 6)    

x2 and y2 will be (7, 0)

Note that x1 x2 y1 y2 can be any points on the line, I just chose these because they were x and y-intercepts.

(6 - 0)/(0 - 7)  =  6/7

The initial value is simply the y-intercept, which is 6.

8 0
3 years ago
Help i will give brainiest
miss Akunina [59]

Answer:

your answer is going to be B: Obtuse

8 0
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