Round 396.6 to 396, because 396/9=44, making a whole number. Hope this helps!!
Answer:
4 pitches
Step-by-step explanation:
if a cylinder with height 9 inches and radius r is filled with water, it can fill a certain pitcher. how many of these pitchers can a cylinder with height 9 inches and radius 2r fill? explain how you know.
Solution:
The volume of a cylinder is given by:
V = πr²h;
where V is the volume, r is the radius of the cylinder and h is the height of the cylinder.
A cylinder with height 9 inches and radius r can fill a certain pitcher. Therefore the volume of the cylinder is:
V = πr²h = πr²(9) = 9πr²
V = volume of pitcher = volume of cylinder with radius r = 9πr²
For a cylinder with height 9 inches and radius 2r its volume is:
V2 = πr²h = π(2r)²(9) = 36πr²
Therefore, the number of pitchers a cylinder with height 9 inches and radius 2r can fill is:
number of pitches = 36πr² / 9πr² = 4
Therefore a cylinder with height 9 inches and radius 2r can fill 4 pitches.
Answer:
y = 1/2x+4
Step-by-step explanation:
First we find the slope
m = (y2-y1)/(x2-x1)
= (3-6)/(-2-4)
= -3/-6
=1/2
The equation of a line in slope intercept form is
y = mx+b where m is the slope and b is the y intercept
y =1/2x+b
Substitute one of the point into the equation
6 = 1/2(4) +b
6 = 2+b
b=4
y = 1/2x+4
I LOVE OUR SWEET MATCHLESS CHRIST JESUS!
The box and whisker plot is attached.
We first order the data from least to greatest:
6, 7, 11, 13, 14, 15, 15, 19, 21
The median is the middle value, or 14.
The lower quartile is the median of the lower half (split by the median). This is between 7 and 11: (7+11)/2 = 18/2 = 9
The upper quartile is the median of the upper half (split by the median). This is between 15 and 19: (15+19)/2 = 34/2 = 17
The highest value is 21.
The lowest value is 6.
We draw the middle line of the box at 14, the median. We draw the left side of the box at the lower quartile, 9. We draw the right side of the box at the upper quartile, 17. From the right side of the box, we draw a whisker to the highest value, 21. From the left side of the box, we draw a whisker to the lowest value, 6.