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Pani-rosa [81]
3 years ago
15

(3,1) and (w,9); slope = -8/3 W= ?

Mathematics
1 answer:
alexandr1967 [171]3 years ago
5 0

Answer:

w=0

Step-by-step explanation:

We know a point (3,1) and the slope (-8/3), so we can use point-slope form, which is y-y1=m(x-x1)

For reference, y1 is the y in the point, m is the slope, and x1 is the x in the point

So we subsitute it

y-1=-8/3(x-3)

do distributive prop.

y-1=-8/3x+8

add 1 to both sides

y=-8/3x+9

This is the equation of the line.

Now to find w, which is the x value.

The point will pass through line, so we can susbtitute the point into the equation.

9=-8/3x+9

subtract 9 from both sides

0=-8/3x

multiply by -3/8 on both sides (the reciprocal of -8/3), we need to isolate x

0=x

x=w

therefore, w=0

Hope this helps!

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-5x-18y=-28 and -10x+9y=-11 solve elimination
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Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=2,\:y=1

Step-by-step explanation:

Given the equations

-5x-18y=-28

-10x+9y=-11

solving the system of the equation by elimination method

\begin{bmatrix}-5x-18y=-28\\ -10x+9y=-11\end{bmatrix}

\mathrm{Multiply\:}-5x-18y=-28\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-10x-36y=-56

\begin{bmatrix}-10x-36y=-56\\ -10x+9y=-11\end{bmatrix}

-10x+9y=-11

-

\underline{-10x-36y=-56}

45y=45

\begin{bmatrix}-10x-36y=-56\\ 45y=45\end{bmatrix}

solve 45y=5 for y:

45y=45

\frac{45y}{45}=\frac{45}{45}

y=1

\mathrm{For\:}-10x-36y=-56\mathrm{\:plug\:in\:}y=1

solve -10x-36\cdot \:1=-56 for x:

-10x-36\cdot \:1=-56

-10x-36=-56

Add 36 to both sides

-10x-36+36=-56+36

-10x=-20

\frac{-10x}{-10}=\frac{-20}{-10}

x=2

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

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