Y = mx + b
slope(m) = -5/2
(-4,4)...x = -4 and y = 4
now we sub and find b, the y int
4 = -5/2(-4) + b
4 = 10 + b
4 - 10 = b
-6 = b
so ur equation is : y = -5/2x - 6....or 5x + 2y = -12
Answer:
60 cm
Step-by-step explanation:
perimeter of big rectangle- 13+13+25+25=76cm
perimeter of smaller rectangle- need to find the width so do 14.6+8.7=23.3
25-23.3=1.7
width of smaller rectangle=1.7
perimeter of smaller rectangle= 1.7+1.7+6.3+6.3=16
Perimeter of the shape= 76-16=60 cm
Answer:
D, A, A, 130, 10
Step-by-step explanation:
99% sure these are correct pls mark brainliest
<h3>
Answer: Choice C. 4*sqrt(6)</h3>
====================================================
Explanation:
Each cube has a side length of 4. Placed together like this, the total horizontal side combines to 4+8 = 8. This is the segment HP as shown in the diagram below. I've also added point Q to form triangle HPQ. This is a right triangle so we can find the hypotenuse QH
Use the pythagorean theorem to find QH
a^2 + b^2 = c^2
(HP)^2 + (PQ)^2 = (QH)^2
8^2 + 4^2 = (QH)^2
(QH)^2 = 64 + 16
(QH)^2 = 80
QH = sqrt(80)
Now we use segment QH to find the length of segment EH. Focus on triangle HQE, which is also a right triangle (right angle at point Q). Use the pythagorean theorem again
a^2 + b^2 = c^2
(QH)^2 + (QE)^2 = (EH)^2
(EH)^2 = (QH)^2 + (QE)^2
(EH)^2 = (sqrt(80))^2 + (4)^2
(EH)^2 = 80 + 16
(EH)^2 = 96
EH = sqrt(96)
EH = sqrt(16*6)
EH = sqrt(16)*sqrt(6)
EH = 4*sqrt(6), showing the answer is choice C
-------------------------
A shortcut is to use the space diagonal formula. As the name suggests, a space diagonal is one that goes through the solid space (rather than stay entirely on a single face; which you could possibly refer to as a planar diagonal or face diagonal).
The space diagonal formula is
d = sqrt(a^2+b^2+c^2)
which is effectively the 3D version of the pythagorean theorem, or a variant of such.
We have a = HP = 8, b = PQ = 4, and c = QE = 4 which leads to...
d = sqrt(a^2+b^2+c^2)
d = sqrt(8^2+4^2+4^2)
d = sqrt(96)
d = sqrt(16*6)
d = sqrt(16)*sqrt(6)
d = 4*sqrt(6), we get the same answer as before
The space diagonal formula being "pythagorean" in nature isn't a coincidence. Repeated uses of the pythagorean theorem is exactly why this is.
Answer: The answers are in the photo.
Step-by-step explanation:
Hope this helps