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3 years ago

What is 5y - 35 = 7x

Mathematics

2 answers:

IgorC [24]3 years ago

5 0

Answer:

y = 7/5x +7

it's a linear function to be a line

Step-by-step explanation:

y = 7/5x +7

it's a linear function to be a line

stepan [7]3 years ago

5 0

7x +5y=35 i think you divide 7 from everything then your able to find your x equal !

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The general formula for an exponential function is
$f(x)=b^x$

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3 years ago

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goldenfox [79]

Answer:

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Step-by-step explanation:

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3 years ago

find the constant m and b in the linear function f(x)=mx+b so that f(6)=9 and the straight line represents by f has slope -4

Charra [1.4K]

Answer:

The constant m=-4, and b=33

Step-by-step explanation:

F(x)= MX+b

If f(6)=9 then x=6, m= -4

9= -4(6) + b

9= -24 + b

b= 9 + 24

b= 33

Therefore the constant m, which is the slope is -4 and b which is the intercept is 33

4 0

3 years ago

In a simple random sample of 14001400 young people, 9090% had earned a high school diploma. Complete parts a through d below.

ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has increased.

Step-by-step explanation:

Let p = proportion of young people who had earned a high school diploma.

A sample of n = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

$\hat p=0.90$

(a)

The standard error for the estimate of the percentage of all young people who earned a high school diploma is given by:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Compute the standard error value as follows:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=\sqrt{\frac{0.90(1-0.90)}{1400}}\\$

$=0.008$

Thus, the standard error for the estimate of the percentage of all young people who earned a high school diploma is 0.0080.

(b)

The margin of error for (1 - α)% confidence interval for population proportion is:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

Compute the critical value of z for 95% confidence level as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the margin of error as follows:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

$=1.96\times 0.0080\\=0.01568\\\approx1.6\%$

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

$CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)$

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has increased, the hypothesis is defined as:

H₀: The percentage of young people who earn high school diplomas has not increased, i.e. p = 0.80.

Hₐ: The percentage of young people who earn high school diplomas has not increased, i.e. p > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of p, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has increased.

8 0

3 years ago

please help! will give brainliest if the answer is correct:) need the answers in order to move on in the lesson!

scZoUnD [109]

Answer:

Just use a calculator and wite the square root value in it

Step-by-step explanation:

Atempt this method with all options at last u will have ur answer

4 0

2 years ago