Answer:
The first 1 on the left is 32 and the 1 on the right is 2. Hence this 8 digits binary number represents 32 + 2 which is the decimal number 34
Explanation:
each 1 represents the number 2 powered by a different number, so starting at the further right, the first number with value 0 is representing , the next on the left which is value 1 is representing which is 2 and so on. So the other 1 further on the left will be which is 32.
Every other digit that is zero is not taking any value, but if they were, they would all be taking values from to Take a look below:
0 0 1 0 0 0 1 0
32 2
Answer:d)the logical grouping of activities in a business process.
Explanation: The logical data flow diagram is the diagram that displays or represents the business related activities.They has easily understandable concept which can be acknowledged by technical as well as non-technical people.They help in providing the data/information by connecting and communicating.
Other options are incorrect because it does not show the process or methods for performing activities neither it works in the form of entities collection in a business..Thus the correct option is option (d).
A diminished triad can be indicated by A lower-case Roman numeral and °.
<h3>How do you Know a diminished triad?</h3>
In any diminished triad, the middle and top two notes of the chord are known to be the flattened and shown by the symbol "o" or "dim."
Therefore, A diminished triad can be indicated by A lower-case Roman numeral and °.
See options from below
A diminished triad can be indicated by:
A) A lower-case Roman numeral and °.
B) A lower-case Roman numeral and +.
C) An upper-case Roman number and °.
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Answer:
If the input is: 2 3 4 8 11 -1
the output is:
Middle item: 4
To explain the given is as follows,
Explanation:
Code:-
#include <iostream>
#include <vector>
using namespace std;
int main()
{
std::vector<int> v;
int temp, i=0;
cout <<"Enter the sorted elements "<<endl;
while(1){
cout<<"Enter ["<<i<<"]element"<<endl;//Accept elements in a vector
cin >> temp;
i++;
if(temp>0)
v.push_back(temp);
else //If negative number is inputed assume end of input
break;
}
cout<<"Size of a vector is:"<<v.size()<<endl; //Find size of vector
if (v.size() % 2 == 0){
cout <<"NUMBER OF ELEMENTS SHOULD BE ODD";
}
else if(v.size()>9){
cout<<"Too many numbers.";
}
else{
cout<<"Median = " << v[v.size()/2]<<endl; //Find median
}
}
Output: