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r-ruslan [8.4K]
3 years ago
13

Explain why the two 1s in this binary number do not have the same value: 00100010​

Computers and Technology
1 answer:
Ahat [919]3 years ago
8 0

Answer:

The first 1 on the left is 32 and the 1 on the right is 2. Hence this 8 digits binary number represents 32 + 2 which is the decimal number 34

Explanation:

each 1 represents the number 2 powered by a different number, so starting at the further right, the first number with value 0 is representing 2^{0}, the next on the left which is value 1 is representing 2^{1} which is 2 and so on. So the other 1 further on the left will be 2^{5} which is 32.

Every other digit that is zero is not taking any value, but if they were, they would all be taking values from 2^{0} to 2^{7} Take a look below:

0  0  1  0  0  0  1  0

       32             2

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4 years ago
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hammer [34]

Answer:

In C++:

#include<iostream>

#include<vector>

using namespace std;

int main() {

int len;

cout<<"Length: ";  cin>>len;

string inpt;

vector<string> vect;

for(int i =0;i<len;i++){

   cin>>inpt;

   vect.push_back(inpt); }

char ch;

cout<<"Input char: ";  cin>>ch;  

for(int i =0;i<len;i++){

   size_t found = vect.at(i).find(ch);  

       if (found != string::npos){

           cout<<vect.at(i)<<" ";

           i++;

       }

}  

return 0;

}

Explanation:

This declares the length of vector as integer

int len;

This prompts the user for length

cout<<"Length: ";  cin>>len;

This declares input as string

string inpt;

This declares string vector

vector<string> vect;

The following iteration gets input into the vector

<em>for(int i =0;i<len;i++){ </em>

<em>    cin>>inpt; </em>

<em>    vect.push_back(inpt); } </em>

This declares ch as character

char ch;

This prompts the user for character

cout<<"Input char: ";  cin>>ch;  

The following iterates through the vector

for(int i =0;i<len;i++){

This checks if vector element contains the character

   size_t found = vect.at(i).find(ch);  

If found:

       if (found != string::npos){

Print out the vector element

           cout<<vect.at(i)<<" ";

And move to the next vector element

           i++;

       }

}  

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