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valentina_108 [34]

3 years ago

5

Jose Escalante worked at a skateboard shop for 40 hours at his regular wage of $7.50. He then worked for 8 hours at his overtime

wage of time and a half. What is the total amount Jose earned?

1 answer:

Naddik [55]3 years ago

5 0

He earned 300 not counting the overtime wage the total gross wage amount would be 390 TOTAL

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How many pounds of blueberries can you buy for $13.00?

Masteriza [31]

Well have many blueberries does it take to make one lbs?

7 0

2 years ago

Read 2 more answers

What is the value of 4x to the third +4x if x is 4

weqwewe [10]

The correct answer of
$4{x}^{2} + 4x$
if x=4 is 272.

to solve the equation if x equals 4, you must substitute the x of the 4.
$4( {4}^{3} ) + 4(4)$
then solve by order of operations.
solve what is inside the parentheses first
$4(64) + 4(4)$
then do the multiplication of the factors
$256 + 16$
then the final step, adding, to get the solution of 272

5 0

3 years ago

If f Superscript negative 1 Baseline (x) = negative one-fifth x, what is f Superscript negative 1 Baseline (x) = one-fifth x?

Artyom0805 [142]

Answer:

a different inverse function

Step-by-step explanation:

If $f^{-1}(x)=-\frac{1}{5}x$ then $f^{-1}(x)=\frac{1}{5}x$ is a different inverse function.

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The second (inverse) function is the first reflected over the y-axis.

5 0

3 years ago

Read 2 more answers

Rewrite the following integral in spherical coordinates.

lora16 [44]

In cylindrical coordinates, we have $r^2=x^2+y^2$ , so that

$z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}$

correspond to the upper and lower halves of a sphere with radius $\sqrt2$ . In spherical coordinates, this sphere is $\rho=\sqrt2$ .

$1 \le r \le \sqrt2$ means our region is between two cylinders with radius 1 and $\sqrt2$ . In spherical coordinates, the inner cylinder has equation

$x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)$

This cylinder meets the sphere when

$x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)$

which occurs at

$\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi$

where $n\in\Bbb Z$ . Then $\frac\pi4\le\phi\le\frac{3\pi}4$ .

The volume element transforms to

$dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi$

Putting everything together, we have

$\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3$

4 0

2 years ago

Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of

Nata [24]

Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
+ 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)

7 0

3 years ago