The slope of this line is m=0
The joint variation that is given in the problem above can be expressed as follows:
w = k/d²
where w is the weight, k is the variation constant, and d is the distance from the center of the earth. Substituting the first scenario to obtain the value of k,
160 = k/(4000)²
k = 2.56 x 10^9
Using this value for the second scenario,
w = (2.56 x 10^9) / (8,000)² = 40 lbs
Thus, the weight of the man, 8000 miles above the center of the earth is 40 lbs.
