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3 years ago

Which is the better deal? $39.55 for 7 pairs of jeans OR $22.48 for 4 pairs of jeans

Mathematics

2 answers:

dimulka [17.4K]3 years ago

8 0

Answer:

I will say %39.56 for 7 pairs because you'll have 7 pair of jeans so you don't have to buy more if some of your jeans rips or something happens so yeah.

scoundrel [369]3 years ago

4 0

Answer:

$39.55 for 7 pairs of jeans

Step-by-step explanation:

The LCM of 7 and 4 is 28, so I decided to use that as an example.

4×7=28

22.48×8=179.84

So if you wanted 28 jeans, you'd be paying $179.84

- - - - -

Now the first deal.

7×4=28

39.55×4=158.2

For 28 jeans, you'd be paying $158.20

For 28 jeans, the first choice offers a better deal than the other.

Mind you, I know the word problem isnt about 28 jeans. But since 28 was the LCM of 4 and 7, I decided to use it as an example

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dimulka [17.4K]

Answer:

$150

Step-by-step explanation:

I feel like this is a trick question

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3 years ago

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What is the simplified term<br> (6^2)(-3^5)

AVprozaik [17]

Answer:

-8748

Step-by-step explanation:

(6^2)(-3^5)

(6 x 6)(-3 x-3 x-3 x -3 x -3)

(36)(-243)

36 x -243

-8748

5 0

3 years ago

What is 14% of $59.99 and how do I figure this problem?

serious [3.7K]

Is/of =%/100 so x/59.99=14%/100 Cross multiply to get the answe

4 0

3 years ago

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Br%7D%7B2%7D%2B%5Cfrac%7Bs%7D%7Br%7D%20-%5Cfrac%7Br%7D%7B4%7D%2B%5Cfrac%7B1%7D%7B5%7D

zloy xaker [14]

Answer:

-1/20

Step-by-step explanation:

r/2 + s/r - r/4 + 1/5 =

= -1/2 + 0/(-1) - (-1)/4 + 1/5

= -1/2 + 1/4 + 1/5

= -10/20 + 5/20 + 4/20

= -5/20 + 4/20

= -1/20

3 0

3 years ago

The altitude of a triangle is increasing at a rate of 1.5 1.5 centimeters/minute while the area of the triangle is increasing at

seraphim [82]

Answer:

The base reduces at 3.75cm/min

Step-by-step explanation:

Given

Let

$h \to altitude$

$b \to base$

$A \to Area$

So:

$\frac{dh}{dt} = 1.5cm/min$

$\frac{dA}{dt} = 1.5^2cm/min$

The area of a triangle is:

$A = \frac{1}{2}bh$

Calculate b when $A =88cm^2; h =8cm$

$A = \frac{1}{2}bh$

$88=\frac{1}{2} * b * 8$

$88 =b * 4$

Solve for b

$b = 88/4$

$b = 22$

We have:

$A = \frac{1}{2}bh$

Differentiate with respect to time

$\frac{dA}{dt} =\frac{1}{2}(h\frac{db}{dt} + b\frac{dh}{dt})$

Substitute the following values in the above equation

$\frac{dh}{dt} = 1.5cm/min$ $\frac{dA}{dt} = 1.5^2cm/min$ $b = 22$ $h = 8$

$1.5 = \frac{1}{2}(8 * \frac{db}{dt} + 22 * 1.5)$

Multiply both sides by 2

$3 = 8 * \frac{db}{dt} + 22 * 1.5$

$3 = 8 * \frac{db}{dt} + 33$

Collect like terms

$8 * \frac{db}{dt} = 3 -33$

$8 * \frac{db}{dt} = -30$

Divide both sides by 8

$\frac{db}{dt} = -\frac{30}{8}$

$\frac{db}{dt} = -3.75$

4 0

3 years ago