It would be 8/10 because you just take the square root of the denominator and the numerator
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>
In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:
f(x) = x² - 5 Given
f' = [(x + h)² - 5 - x² + 5] / h Definition of derivative
(x² + 2 · x · h + h² - 5 - x² + 5) / h Perfect square trinomial
(2 · x · h + h²) / h Associative, commutative and modulative properties / Existence of additive inverse
2 · x + h Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse
2 · x h = 0 / Result
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
To learn more on derivatives: brainly.com/question/25324584
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D is the answer for the question
Answer:
2x³ + 12x² + 10x - 24
Step-by-step explanation:
(2x² + 6x - 8)(x + 3) Distribute
2x³ + 6x² + 6x² + 18x - 8x - 24 Combine like terms
2x³ + 12x² + 10x - 24 This expression is in standard form
If this answer is correct, please make me Brainliest!
Answer:
C. x = -12 and x = 2
Step-by-step explanation:
-x²-10x+24=0 Original equation
x²+10x-24=0 Divide everything by -1
(x+12)(x-2)=0 Factor it out
x=-12,2 Solve so that the inside of the parentheses equals 0
