Given the figure of a cyclic quadrilateral
The sum of the opposite angles = 180
so, we can write the following equations:
we will find (x) from equation (1):
x = 180 - 100 = 80
We will find (y) from equation (2):
2y = 180 - 102
2y = 78
y=78/2 = 39
So, the answer will be:
x = 80
y = 39
It's the slope-point formula:
We have:
Therefore, the slope
The attached graph represents the location of the pH values 0 and 1
<h3>How to plot the points?</h3>The given parameters are:
pH value 0 = (1, 0)
pH value 1 = (0.1, 1)
This means that we plot a point at the coordinate (1, 0) and another point at the coordinate (0.1, 1).
See attachment for the graph
Read more about graphs at:
#SPJ1
<u>Complete question</u>
The pH value is 0 at (1, 0) and 1 at (0.1, 1).
Using desmos
A. Locate, plot, and label on your graph where the pH value is 0.1
B. Locate, plot, and label on your graph where the pH value is 1.
