PV = P(1 - (1 + r)^-n) / r; where P is the periodic withdrawal = $100,000; r = rate = 5% = 0.05; n = number of periods = 20 years.
PV = 100000(1 - (1 + 0.05)^-20) / 0.05 = 100000(1 - 1.05^-20) / 0.05 = 100000(1 - 0.3769) / 0.05 = 100000(0.6231) / 0.05 = 100000(12.4622) = 1,246,221 ≈ $1,250,000
Adding more short sentences.
For this case we have the following fraction:
(1-cos ^ 2 (θ)) / (sin ^ 2 (θ))
We must take into account the following trigonometric identity:
cos ^ 2 (θ) + sin ^ 2 (θ) = 1
Therefore rewriting we have:
sin ^ 2 (θ) = 1 - cos ^ 2 (θ)
Substituting in the given fraction we have:
(1-cos ^ 2 (θ)) / (sin ^ 2 (θ))
= (sin ^ 2 (θ)) / (sin ^ 2 (θ))
= 1
Answer:
1
Answer: its A
Step-by-step explanation:
