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Nina [5.8K]
3 years ago
12

How do i solve my math problem (5 carry 3 on top) carry 3 on top again

Mathematics
2 answers:
kvasek [131]3 years ago
7 0
The answer will be 11. Hope it help!
choli [55]3 years ago
6 0
It is 11 because 5 carry 3, so then we have 8, carry 3 on top of 8, it equals 11.


Hope this helps you :)
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3(a+1.5)=-1.5 <br> what value of a makes the equation true?
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Answer:

The answer is a= -2

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Please help with question 6
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y = -3x - 1

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The sum of two numbers is 40 one number is 4 times as large as the other what are the numbers
MAXImum [283]
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Read 2 more answers
This question refers to unions and intersections of relations. Since relations are subsets of Cartesian products, their unions a
Mice21 [21]

Answer:

AXB= = {(x, y) ∈ A ✕ B| x ∈ A , y ∈  B}

R= {(x, y) ∈ A ✕ B| x R y ⇔ |x| = |y|}

S={(x, y) ∈ x A ✕ B | S y ⇔ x − y is even}

R ∪ S= {(x, y) ∈ A ✕ B | (x, y) ∈ R or (x, y) ∈ S}

R ∩ S = {(x, y) ∈ A ✕ B | (x, y) ∈ R and (x, y) ∈ S}

Step-by-step explanation:

Let A = {−4, 4, 7, 9} and B = {4, 7},

Then A X B= { (-4,4),(-4,7),(4,4),(4,7),(7,4),(7,7),(9,4),(9,7)}

AXB contains all elements of A and B such that x from A and y is from B.

AXB= = {(x, y) ∈ A ✕ B| x ∈ A , y ∈  B}

R= {(-4,4),(4,4),(7,7)}

R consists all ordered pairs where  |x| = |y|

R= {(x, y) ∈ A ✕ B| x R y ⇔ |x| = |y|}

S= { (-4,4),(4,4),(7,7)}

S={(x, y) ∈ x A ✕ B | S y ⇔ x − y is even}

S consists all ordered pairs where x-y is even.

R ∪ S, = { (-4,4),(4,4),(7,7)}

R US is a set containing subsets of both sets R and S

R ∪ S= {(x, y) ∈ A ✕ B | (x, y) ∈ R or (x, y) ∈ S}

R ∩ S=  {(-4,4),(4,4),(7,7)}

R ∩ Sis a set containing subsets only which are common between sets R and S

R ∩ S = {(x, y) ∈ A ✕ B | (x, y) ∈ R and (x, y) ∈ S}

8 0
3 years ago
Solve the system of equations. −9y+4x−20=0−7y+16x−80=0\begin{aligned} &amp;-9y+4x - 20=0 \\\\ &amp;-7y+16x-80=0 \end{aligned} ​
gulaghasi [49]

Answer:

  • (x, y) = (5, 0)

Step-by-step explanation:

\begin{aligned} &-9y+4x - 20=0 \\ &-7y+16x-80=0 \end{aligned}

Subtract 4 times the first equation from the second:

  (-7y +16x -80) -4(-9y +4x -20) = (0) -4(0)

  29y = 0 . . . . . simplify

  y = 0 . . . . . . . .divide by 29

  4x -20 = 0 . . . . substitute 0 for y in the first equation

  x -5 = 0 . . . . . .divide by 4

  x = 5 . . . . . . . . add 5

The solution to this system is (x, y) = (5, 0).

7 0
3 years ago
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