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Elza [17]
3 years ago
8

A hospital estimates that, based on past experience, it will incur $5 million in malpractice claims as a result of services rend

ered in the current period. The hospital carries a malpractice insurance policy with a yearly $2 million deductible clause. The amount that should appear on its year-end financial statement as Claims Expense (Loss) should be
a) $0.b) $2 million.c) $3 million.d) $5 million.
Business
1 answer:
Gala2k [10]3 years ago
5 0

Answer:

d) $5 million.

Explanation:

The amount that should appear on the year-end financial statement should be the most probable estimate. In this case, $5 million is the most probable because this is deduced from past experience, while $2 million is a practice that should be reviewed in the light of new information.

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The Nandina Corporation was formed and began operations on July 1, 2018, and incurred the following expenses during the year: St
Cerrena [4.2K]

Answer:

$110.00

Explanation:

Nandina Corporation

The amount of amortization expenses for 2018

State fees for incorporation $800

Legal and accounting fees incident to organization 1,500

Temporary directors’ fees 1,000

Total $3,300

Hence:

$3,300/180 months x 6 months

= $110.00

Therefore the amount of its amortization expense for 2018 will be $110.00

4 0
3 years ago
Interactive sites where users write about personal topics and comment to a threaded discussion are called
Masja [62]
The correct answer is blogs.
4 0
4 years ago
James, a casino manager, defines and uses signals and symbols to influence corporate culture by communicating central values to
matrenka [14]

Answer: Cultural Leadership

Explanation:

A) Egalitarian leader is WRONG

B) Cultural Leader: This is the kind of leader that instills cultural heritage such as customs, believe, past stories and values in his/her subodinate as in the case of James who uses signals and symbols to influence corporate culture by communicating central values to employees.

C) Servant Leader is WRONG. It can be likened to a leader that performs almost all the duties of the subodinate

D) Totalitarian Leader is also WRONG

E) Transitional Leader is WRONG

8 0
3 years ago
Kent Manufacturing produces a product that sells for $50.00 and has variable costs of $24.00 per unit. Fixed costs are $260,000.
Verdich [7]

Answer:

d. 9,200 units.

Explanation:

The computation is shown below for break-even points in units:

= (Fixed expenses ) ÷ (Contribution margin per unit)  

where,  

Fixed costs = $260,000 + $11,400 = $271,400

Contribution margin per unit = Selling price per unit - variable cost per unit

= $50 - $20.5

= $29.5

Now put these values to the above formula  

So, the units would equal to

= $271,400 ÷ $29.5

= 9,200 units

7 0
3 years ago
Suppose the world population today is 7 billion, and suppose this population grows at a constant rate of 3% per year from now on
oksano4ka [1.4K]

Answer:

a) P(t=100) = 7 e^{0.03*100}=140.599 billion

b) P(t=0) = 7 e^{0.03*0}=7 billion

P(t=1) = 7 e^{0.03*1}=7.21 billion

P(t=2) = 7 e^{0.03*2}=7.43 billion

P(t=10) = 7 e^{0.03*10}=9.45 billion

P(t=25) = 7 e^{0.03*25}=14.82 billion

P(t=50) = 7 e^{0.03*50}=31.37 billion

c) Figure attached

d) Figure attached

Explanation:

The proportional model on this case would be given by:

\frac{dP}{dt} = kP

Where P is the population size, t the time on years and k a constant.

We can reorder this expression like this:

\frac{dP}{P} = k dt

If we integrate both sides we got:

ln|P| = kt + C

And using exponentials on both sides we got:

P(t) = e^{kt} e^C = P_o e^{kt}

Where P_o=7 billion  represent the initial amount for the starting year t=0.

The rate on this case is given r =3\% = 0.03, so then our model would be given by:

P(t) = 7 e^{0.03t}

Part a

For this case we just need to replace t=100 and we got:

P(t=100) = 7 e^{0.03*100}=140.599 billion

Part b

For this case we have the following:

P(t=0) = 7 e^{0.03*0}=7 billion

P(t=1) = 7 e^{0.03*1}=7.21 billion

P(t=2) = 7 e^{0.03*2}=7.43 billion

P(t=10) = 7 e^{0.03*10}=9.45 billion

P(t=25) = 7 e^{0.03*25}=14.82 billion

P(t=50) = 7 e^{0.03*50}=31.37 billion

Part c

The graph is on the first figure attached.

Part d

If we take a log-log scale we have the following values

We need to exclude the point t=0 since the natural log for 0 is not defined.

ln 1 =0 , ln 2= 0.693, ln 10=2.30, ln 25 =3.22, ln 50= 3.91

The result would be the figure 2 attached. And we see a better result for the graph.

3 0
3 years ago
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