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const2013 [10]
3 years ago
7

(2^3)^7 (2^-9)^2 how do i put that in exponential form​

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer:

2³ = 8

Step-by-step explanation:

According to the laws of exponents, when raising a power to another power, you need to multiply the exponents.  After you multiply each set of exponents by the additional power, then it become a multiplication problem where the base is the same.  When multiplying exponents with the same base, you keep the base and add the exponents:  

(2^{3})^{7}*(2^{-9})^{2}=2^{21}*2^{-18}=2^{21+-18}=2^{3}

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