3 years ago

Use this graph to answer these questions.

1 answer:

5 0

The answer is D I think

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Shtirlitz [24]

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Mariana [72]

$x^2 - 12x + 36 = 90 \\ (x-6)^2=90\\ x-6=\sqrt{90} \vee x-6=-\sqrt{90}\\ x=6+3\sqrt{10} \vee x=6-3\sqrt{10}$

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ELEN [110]

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3 years ago

Elanso [62]

Answer:

The given equation will have two roots as +5i and -5i

Step-by-step explanation:

Shasta claimed that the equation x^2+25=0 can be solved by using its factored form of (x+5i)^2=0, and that -5i is the only zero for this function

The given equation is $x^2+25 =0$

This clearly shows it will have complex roots, and since it is a quadratic equation it will have 2 complex roots

$x^2 = -25 \\x = \sqrt{-25} \\x= \sqrt{-1}* \sqrt{25}\\$

$x = i\sqrt{25}$

x = ± 5i

It will be false to say that -5i will be the only complex root to this equation.

The given equation will have +5i and -5i as its roots.

Lets verify

x = +5i

$(5i)^2 + 25 \\25i^2 + 25 \\25(-1) + 25\\-25 + 25 = 0$

x = -5i

$(-5i)^2 + 25 \\25i^2 + 25 \\25(-1) + 25 \\-25 + 25 \\ = 0$

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3 years ago

olga2289 [7]

Step-by-step explanation:

where is the question?..

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3 years ago