These two polygons are both rectangles, so the angles are preserved. We must check the sides, and we have to check if the smaller sides are in the same proportion as the bigger sides.

So, the two rectangles are similar if the following is true.

$4\div 5 = 11\div 12$

In any proportion, the product of the inner terms must be the same as the product of the outer terms:

$4\cdot 12 = 5\cdot 11 \iff 48=55$

This is clearly false, and thus the two rectangles are not similar.

5 0

3 years ago

PLEASE HELP ASAP !!!!!!!!!!!!!!!!!!!!!!!!!

disa [49]

Answer:

C. 15 votes

Step-by-step explanation:

B= votes Billy got

K = votes Keeton got

B = 3K

B+K =20

Substitute the first equation into the second equation

3K + K =20

Combine like terms

4K =20

Divide both sides by 4

4K/4 = 20/4

K =5

Keeton got 5 votes

B = 3*K

B = 3*5

B = 15 votes

Billy got 15 votes

3 0

3 years ago

You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu

aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to $180^{o}$ .

Let the exterior angle be represented by $x^{o}$ , and the three interior angles of the triangle be represented by $a^{o}$ , $b^{o}$ and $c^{o}$ .

Assume that the vertex angle $c^{o}$ is the linear pair to the exterior angle $x^{o}$ .

i.e $x^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles on a straight line)

Thus,

i. $a^{o}$ + $b^{o}$ = $x^{o}$ (sum of two opposite interior angles is equal to an exterior angle)

⇒ $a^{o}$ = $x^{o}$ - $b^{o}$

Also,

$b^{o}$ = $x^{o}$ - $a^{o}$

But,

$a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

⇒ $c^{o}$ = $180^{o}$ - ( $a^{o}$ + $b^{o}$ )

and

$a^{o}$ + $b^{o}$ = $180^{o}$ - $c^{o}$

ii. $a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

$a^{o}$ = $180^{o}$ - ( $b^{o}$ + $c^{o}$ )

Also,

$a^{o}$ + $b^{o}$ = $x^{o}$

⇒ $b^{o}$ = $x^{o}$ - $a^{o}$

$c^{o}$ = $180^{o}$ - $x^{o}$

8 0

3 years ago