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3 years ago

6

(09.08)

1 answer:

galina1969 [7]3 years ago

6 0

I think that the answer would come out to be A

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The area of a circle is 100 square miles. What is the diameter?

adell [148]

Answer:

The diameter of a circle with an area of 100 square miles is 20/√π miles.

Step-by-step explanation:

Area =100 = πr^2.

diameter = d = 2r.

100 = πr^2.

100/π = r^2.

√(100/π) = r.

10/√π = r.

d = 2r.

d = 2 * 10/√π.

d = 20/√π

5 0

3 years ago

Write the following numbers used in these statements in scientific notation. (Note: Some of these numbers have been rounded.)

VARVARA [1.3K]

Answer:

So 0.0000214 can be written as $2.14\times 10^{-9}cubic\ yard$

Step-by-step explanation:

We have given one cubic inch = 0.0000214 cubic yard

We have to convert this into scientific notation

We know that 0.0000214 can be written as $\frac{214}{10000000}$

We know that $\frac{1}{10}$ can be written as $10^{-1}$

So $\frac{1}{10000000}$ can be written as $10^{-7}$

So $\frac{214}{10000000}$ can be written as $214\times 10^{-7}=2.14\times 10^{-9}cubic\ yard$

3 0

4 years ago

What is the answer for X-5(x-1)=x(2x-3) ?

Mandarinka [93]

Answer:

1 2/3

Step-by-step explanation:

x-5x+5=2x-3x

-4x+5= -1x

5=3x

5/3=x

1 2/3=x

6 0

3 years ago

Read 2 more answers

What is the solution to the given inequality? one-half minus one-fourth x is greater than or equal to negative one-fourth x –1 x

borishaifa [10]

Answer:

x ≤ 3

Just took the assignment, i hope you have a good day :)

8 0

3 years ago

Read 2 more answers

a lunch stand makes a $.75 profit on each chef's salad and $1.20 profit on each caesar salad. On a typical weekday, it sells bet

tangare [24]

Answer:

<em>50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.</em>

Step-by-step explanation:

Suppose, the number of Chef's salad is $x$ and the number of Caesar salad is $y$

On a typical weekday, it sells between 40 and 60 Chefs salads and between 35 and 50 Caesar salads.

So, the two constraints are: $40\leq x\leq 60$ and $35\leq y\leq 50$

The total number sold has never exceed 100 salads. So, another constraint will be: $x+y\leq 100$

According to the graph of the constraints, the vertices of the common shaded region are: $(40,35), (60,35), (60,40), (50,50)$ and $(40,50)$ <em>(Refer to the attached image for the graph)</em>

The lunch stand makes a $.75 profit on each Chef's salad and $1.20 profit on each Caesar salad. So, the profit function will be: $P=0.75x+1.20y$

For (40, 35) , $P=0.75(40)+1.20(35)=72$

For (60, 35) , $P=0.75(60)+1.20(35)=87$

For (60, 40) , $P=0.75(60)+1.20(40)=93$

For (50, 50) , $P=0.75(50)+1.20(50)=97.5$ <u><em>(Maximum)</em></u>

For (40, 50) , $P=0.75(40)+1.20(50)=90$

Profit will be maximum when $x=50$ and $y=50$

Thus, 50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.

6 0

4 years ago