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IgorC [24]
3 years ago
6

Alexis put $2000 in a savings account. After 4 years, she had $2543 in the account. What rate of interest did she earn? Use the

formula A= Pe^rt, where A is the ending amount, P is the principal (initial amount), r is the interest rate, and t is time.
Mathematics
2 answers:
Flauer [41]3 years ago
5 0
This is substitution, it's very simple once you get the hang of it! 

okay, what you want to do is plug in the numbers you already have, to get the number you don't have(r).

First, you plug in the numbers.

1.  P= $2000  
    A=$2543
    t= 4(years)
    r=? 

2543=2000^r(4) 

Secondly, you want to solve the equation.


Elena L [17]3 years ago
3 0

Answer:

Rate of interest = 6%

Step-by-step explanation:

Alexis put $2000 in a savings account. After 4 years, she had $2543 in the account.

Use the formula,

A=Pe^{rt}

P\rightarrow \$2000

r\rightarrow ?

A\rightarrow \$2543

t\rightarrow 4\text{ years}

Substitute the value into formula and solve r

2543=2000e^{4r}

e^{4r}=1.2715

Apply ln both sides

4r\ln(e)=\ln(1.2715)

r=0.06

Rate of interest = 6%

Hence, The rate of interest is 6%

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Crank

Answer:

A is -2

B is 2

C is 4

Step-by-step explanation:

So just replace each letter with these numbers and do the math, hope this helps

4 1
3 years ago
Let Upper A equals left bracket Start 2 By 2 Matrix 1st Row 1st Column negative 2 2nd Column 4 2nd Row 1st Column 1 2nd Column 3
Anastaziya [24]

Answer:

See explanation

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]

B=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]

A. Find AB:

AB=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]\cdot \left[\begin{array}{cc}-2&1\\3&7\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+4\cdot 3&-2\cdot 1+4\cdot 7\\1\cdot (-2)+3\cdot 3&1\cdot 1+3\cdot 7\end{array}\right]=\left[\begin{array}{cc}16&26\\7&22\end{array}\right]

B. Find BA:

BA=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]\cdot \left[\begin{array}{cc}-2&4\\1&3\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+1\cdot 1&-2\cdot 4+1\cdot 3\\3\cdot (-2)+7\cdot 1&3\cdot 4+7\cdot 3\end{array}\right]=\left[\begin{array}{cc}5&-5\\1&33\end{array}\right]

C. Answers are not the same

D. Matrices multiplication is not commutastive in general, so

AB\neq BA

7 0
3 years ago
A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7). What are the vertices of r(90, O)(WXYZ)?
VashaNatasha [74]

Given:

A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).

Rule of rotation is r_{(90^\circ, O)}(WXYZ).

To find:

The vertices after rotation.

Solution:

We know that, r_{(90^\circ, O)}(WXYZ) means 90 degrees counterclockwise rotation around the origin.

So, the rule of rotation is defined as

(x,y)\to (-y,x)

Using this rule, we get

W(3,-5)\to W'(5,3)

X(1,-3)\to X'(3,1)

Y(-1,-5)\to Y'(5,-1)

Z(1,-7)\to Z'(7,1)

Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).

8 0
3 years ago
-2x
mars1129 [50]

y=0

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6 0
3 years ago
Convert 221 quinary number into decimal number.​
aleksley [76]

Step-by-step explanation:

<h2>______________________</h2>

( First of all to convert quinary to decimal we need to multiply them by 5 )

So let's solve now.....

= 221

Solution,

Converting quinary number to decimal .....

= 2 × 5² + 2 × 5¹ + 1 × 5⁰

The value of any number to the power 0 is 1 ...

= 2 × 25 + 2 × 5 + 1 × 1

= 50 + 10 + 1

= 61..

<h2>______________________</h2>

Hence the answer is 61....

<h2>______________________</h2>
6 0
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