Answer:
(2, - 1 )
Step-by-step explanation:
3x - y = 7 → (1)
2x + 3y -= 1 → (2)
multiplying ( 1) by 3 and adding to (2) will eliminate y
9x - 3y = 21 → (30
add (2) and (3) to eliminate y
11x = 22 (divide both sides by 2 )
x = 2
substitute x = 2 into either of the 2 equations and solve for y
substituting into (2)
2(2) + 3y = 1
4 + 3y = 1 (subtract 4 from both sides )
3y = - 3 ( divide both sides by 3 )
y = - 1
solution = (2, - 1 )
Answer:
9.50
Step-by-step explanation:
Answer: B
Step-by-step explanation: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:
24x2+25x−47=(−8x−3)(ax−2)−53
You should then multiply (−8x−3) and (ax−2) using FOIL.
24x2+25x−47=−8ax2−3ax+16x+6−53
Then, reduce on the right side of the equation
24x2+25x−47=−8ax2−3ax+16x−47
Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.
The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is the longer option, and I do not recommend it for the actual SAT as it will waste too much time.
The final answer is B.
The answer would be 1.637 since you have already reached the 100 mark (hence the 1. at the beginning) and you still have 63.7 percent extra making up that .637 since the decimal spaces have been moved so that the correct decimal places may correlate to the percentage given
Answer:
Check below, please
Step-by-step explanation:
Hello!
1) In the Newton Method, we'll stop our approximations till the value gets repeated. Like this
2) Looking at the graph, let's pick -1.2 and 3.2 as our approximations since it is a quadratic function. Passing through theses points -1.2 and 3.2 there are tangent lines that can be traced, which are the starting point to get to the roots.
We can rewrite it as:
As for
3) Rewriting and calculating its derivative. Remember to do it, in radians.
For the second root, let's try -1.5
For x=-3.9, last root.
5) In this case, let's make a little adjustment on the Newton formula to find critical numbers. Remember their relation with 1st and 2nd derivatives.
For -1.2
For x=0.4
and for x=-0.4
These roots (in bold) are the critical numbers