5 is your answer
1: 5 = 5: 25
Note that the colon can act like a fraction.
Simplify 5/25.
(5/25)/(5/5) = 1/5 = 1/5
5 is your answer
hope this helps
Answer:
(1, 10)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
-5x + 6y = 55
4x + 3y = 34
<u>Step 2: Rewrite Systems</u>
4x + 3y = 34
- Multiply everything by -2: -8x - 6y = -68
<u>Step 3: Redefine Systems</u>
-5x + 6y = 55
-8x - 6y = -68
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Combine equations: -13x = -13
- Divide -13 on both sides: x = 1
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 4x + 3y = 34
- Substitute in <em>x</em>: 4(1) + 3y = 34
- Multiply: 4 + 3y = 34
- Isolate <em>y</em> term: 3y = 30
- Isolate <em>y</em>: y = 10
If you are looking to find the value of x then you have to use distributive property.
1st: multiply -3 by 2x and 4 -3(2x+4)
-6x -12
2nd: do the same thing on the other side which is multiply 3 by x and -6
3(x-6)
3x-18
3rd: Then you have -6x-12=3x-18
+12 +12
add 12 to each side so then you have -6x=3x-6
then divide by -6 on each side and the answer is x= 2/3
Given:
μ = 55 in, population mean
σ = 6 in, population standard deviation
Part (a)
x = 48 in, the random variable
Calculate the z-score.
z = (x - μ)/σ
= (48 - 55)/6
= -1.667
From standard table, obtain
P(X < 48) = 0.12167
Answer: 0.1217 (tyo 4 dec.places)
Answer:
Option A. is the correct option.
Step-by-step explanation:
If a number is divisible by 5 it is not necessary that the number will be divisible by 10.
For example: 25 is the number divisible by 5 but not divisible by 10.
Or in other words a number divisible by 5 should be even to be divisible by 10.
So for the conditional statement : A number is divisible by 10 if and only if it is divisible by 5 will be false because any one out of these two statements is false. We know biconditional is true only when both the statements are true or false means both the statements should have same truth value.
Therefore Option A. is the correct option.
