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Anuta_ua [19.1K]
3 years ago
7

Two cyclists start at the same point and travel in opposite directions. One cyclist travels 4 km per hour faster than the other.

If the two cyclists are 240 km apart after 4 hours, what is the rate of each cyclist?​

Mathematics
1 answer:
yaroslaw [1]3 years ago
5 0

Answer:

the rate of the first cyclist: 28km/h

the rate of the 2nd cyclist 28+4= 32km/h

Step-by-step explanation:

x= the rate of the first cyclist

x+4= the rate of the 2nd cyclist

after 4 hours: + the first cyclist travels 4x  (km)

                       + the 2nd cyclist travels 4(x+4)  (km)

because the two cyclists are 240 km apart after 4 hours

=> 4x + 4(x+4) = 240 => x= 28

i hope it's useful forr u =)))

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1. 7p - 6pc + 3c - 2 Number of terms: Coefficients: Constant terms:​
Andreas93 [3]

Step-by-step explanation:

Given:

7p - 6pc + 3c - 2

Find:

Number of terms

Coefficients

Constant terms

Computation:

Number of terms = 4

Coefficients = (7, -6, 3)

Constant terms = -2

8 0
3 years ago
Please help I'm clueless! I'll give brainliest!
Marianna [84]

Answer:

33%

Step-by-step explanation:

The logo can be divided into three...

1. The inner circle (or The White Circle)

2. Blue + White circle

3. The whole circle(The logo)

I will be calculating the area of each circle..

Area of circle = (pi)r²

pi = 22/7

The inner circle

radius = 4cm

Area = 22/7 × 4²

= 50.286 cm² or 50²/7 cm²

Blue + White Circle

radius = 4 + 3 = 7cm

Area = 22/7 × 7²

= 154 cm²

The whole circle

radius = 4 + 3 +3 = 10cm

Area = 22/7 × 10²

= 314.286 cm² or 314²/7 cm²

Area shaded blue =

Area of [(Blue + White circle) - (The white circle)]

= 154 - 50.286 = 103.714 cm² or 103.⁵/7 cm²

Percentage of logo shaded blue =

(Area shaded blue) / (Area of logo) × 100

= 103.714/314.286 × 100

= 32.9999%

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8 0
3 years ago
please help me with my question due tomorrow morning I will like and mark as brainliest for the first correct answer please​
galina1969 [7]

Answer:

p = (2k + 1)i + j

q = 25i + (k + 4)j

p . q = 11

Find the dot product of p and q

(2k + 1)(25) + (k + 4) = 11

50k + 25 + k + 4 = 11

51k = -18

k = - 18/51 = –6/17.✅

b) p.q = |p||q|cos∅

p= (2k + 1)i + j = [2(-6/17) + 1)i + j ]= 5/17i + j

|p| = √ (5/17)² + 1²

|p| = √314/ 17 ( The square root doesn't cover the 17) = 1.0424

q = 25i + (k + 4)j = 25i + ( -6/17 + 4)j

q = 25i + 62/17 j

|q| = √ 25² + (62/17)²

= 25.2646

Now applying them to the formula above

We already have p.q = 11 from the question.

11 = (1.0424)(25.2646)Cos∅

11 = 26.3358Cos∅

Cos∅ = 11/26.3358

Cos∅ = 0.4177

∅ = 65.31°.

This should be it.

Hope it helps

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Tcecarenko [31]

Answer:

Step-by-step explanation:

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