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aleksandr82 [10.1K]
3 years ago
11

What percent of 3.5 is 21?

Mathematics
1 answer:
Masteriza [31]3 years ago
5 0
20% good luck on your test
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PLSSSSSSSSSSSSSS HELP <3
Komok [63]

1. Given

2. AD is parallel to BC

3. ∠3 ≅ ∠2

4. transitive property of congruence

5. Definition of bisect

3 0
3 years ago
Reduce in standard form -3/-15​
andriy [413]

Answer:

1/5? 0.2?

Step-by-step explanation:

5 0
2 years ago
20 square root of 270 /4 square root of 3
OleMash [197]

Answer:

<u>The most simplified form is 15√10</u>

Step-by-step explanation:

1. Let's simplify the expression:

20√270 ÷ 4√3

20√9 * 30/  4√3 (√270 = √9 * 30)

60 √30/ 4√3

(60 √3 * √10) / 4√3 (√30 = √3 * √10)

60/4 √10 ( We cancel √3 in the numerator and in the denominator)

15√10

<u>The most simplified form is 15√10</u>

6 0
3 years ago
Factorise completely:<br> 1. 3xy - x<br>2. 4a² - 9​
Amanda [17]

Answer:

x(3y - 1) and (2a - 3)(2a + 3)

Step-by-step explanation:

(1)

3xy - x ← factor out x from each term

= x(3y - 1)

(2)

4a² - 9 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

4a² - 9

= (2a)² - 3²

= (2a - 3)(2a + 3)

6 0
2 years ago
in a standard casino dice game the roller wins on the first roll if he rolls a sum of 7 or 11. what is the probability of winnin
Alborosie

<u>Answer-</u>

<em>The probability of winning on the first roll is </em><em>0.22</em>

<u>Solution-</u>

As in the game of casino, two dice are rolled simultaneously.

So the sample space would be,

|S|=6^2=36

Let E be the event such that the sum of two numbers are 7, so

E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

|E|=56

\therefore P(E)=\dfrac{|E|}{|S|}=\dfrac{6}{36}

Let F be the event such that the sum of two numbers are 11, so

F = {(6,5), (5,6)}

|F|=2

\therefore P(F)=\dfrac{|F|}{|S|}=\dfrac{2}{36}

Now,

P(\text{sum is 7 or 11)}=P(E\ \cup\ F)=P(E)+P(F)=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}=0.22

8 0
3 years ago
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