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anzhelika [568]
3 years ago
15

Tanya tiene un jardin con un foso alrededor. El jaidim el un rectangulo de 2 1/2m de largo y 2m de ancho. El jardin y el foso ju

ntos forman un rectangulo de 3 1/2m de largo y 3m de ancho. Encuantra la area del foso solo

Mathematics
1 answer:
professor190 [17]3 years ago
4 0

Answer:

El área del foso es 5.5 m²

Step-by-step explanation:

Hola!

Por favor, mira el esquema adjunto para una descripción del problema.

Viendo la figura, podemos deducir que el área del foso será igual al área del rectángulo formado por el jardín y el foso menos el área del jardín.

Área del foso = área del foso y jardín - área del jardín.

El área de un rectángulo se calcula multiplicando la longitud de la base por la altura:

Área del jardín = 2.5 m · 2 m = 5 m²

Área del rectángulo jardín - foso = 3.5 m · 3 m = 10.5 m²

Área del foso = 10.5 m² - 5 m² = 5.5 m²

El área del foso es 5.5 m²

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The Genetics &amp; IVF Institute conducted a clinical trial of the YSORT method designed to increase the probability of conceivi
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Step-by-step explanation:

We know that the probability of giving birth to a boy : p= 0.5

i..e The population proportion of giving birth to a boy =  0.5

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Alternative hypothesis :  H_a: p>0.5

Since H_a is right-tailed , so the hypothesis test is a right-tailed z-test.

Also, it is given that , the sample size : n= 291

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Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} , where n is sample size ,  \hat{p} is sample proportion and p is the population proportion.

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2 years ago
What is the coordinates of the center of an ellipse defined by the equation 16x^2 + 25y^2 + 160x - 200y + 400 = 0 ? Please give
pickupchik [31]

16x^2 + 25y^2 + 160x - 200y + 400 = 0     Rearrange and regroup.

(16x^2 + 160x) + (25y^2 - 200y ) = 0-400.     Group the xs together and the ys together.

16(X^2 + 10x) + 25(y^2-8y) = -400.     Factorising.

We are going to use completing the square method.

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Square it = 5^2  = 25.     (Note this value)


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Half of it = 1/2 * -8 = -4. (Note this value)

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We are going to carry out a manipulation of completing the square with the values

25 and 16.  By adding and substracting it.


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Note that +25 - 25 = 0.    +16 -16 = 0. So the equation is not altered.

16(X^2 + 10x + 25) -16(25) + 25(y^2-8y + 16) -25(16) = -400


16(X^2 + 10x + 25) + 25(y^2-8y + 16)  = -400 +16(25) + 25(16)    Transferring the terms -16(25) and -25(16)

to other side of equation.  And 16*25 = 400


16(X^2 + 10x + 25) + 25(y^2-8y + 16)  = 25(16)


16(X^2 + 10x + 25) + 25(y^2-8y + 16)  = 400

We now complete the square by using the value when coefficient was halved.


16(x-5)^2 + 25(y-4)^2  = 400

Divide both sides of the equation by 400


(16(x-5)^2)/400 + (25(y-4)^2)/400  = 400/400              Note also that, 16*25 = 400.


((x-5)^2)/25 + ((y-4)^2)/16  = 1

((x-5)^2)/(5^2) + ((y-4)^2)/(4^2)  = 1


Comparing to the general format of an ellipse.

((x-h)^2)/(a^2) + ((y-k)^2)/(b^2)  = 1


Coordinates of the center = (h,k).

Comparing   with above   (x-5) = (x - h) , h = 5.

Comparing   with above   (y-k) = (y - k) , k = 4.

Therefore center = (h,k) = (5,4).

Sorry the answer came a little late.  Cheers.

3 0
3 years ago
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