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In-s [12.5K]
3 years ago
7

What is (f−g)(x)?

Mathematics
1 answer:
Oxana [17]3 years ago
6 0

Answer:

\large\boxed{(f-g)(x)==3x^5-2x^4-x^2+x-21}

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)\\\\\text{We have}\\\\f(x)=3x^5+6x^2-5\\\\g(x)=2x^4+7x^2-x+16\\\\\text{substitute:}\\\\(f-g)(x)=(3x^5+6x^2-5)-(2x^4+7x^2-x+16)\\\\=3x^5+6x^2-5-2x^4-7x^2+x-16\\\\\text{combine like terms}\\\\=3x^5-2x^4+(6x^2-7x^2)+x+(-5-16)\\\\=3x^5-2x^4-x^2+x-21

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Suppose Jamal visits a record store with 788 records. If 264 of the records are from the years 1975 to 1979 and Jamal selects a
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3 0
2 years ago
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1) f(x) = 2x + 4, g(x) = 4x2 + 1; Find (g ∘ f)(0).
Sholpan [36]

Answer:

<h2>(g \: \circ \: f)(0) = 17</h2>

Step-by-step explanation:

f(x) = 2x + 4

g(x) = 4x² + 1

In order to find (g ∘ f)(0) we must first find

(g ° f )(x)

To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)

That's

<h3>(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\  = 4(4 {x}^{2}  + 16x + 16) + 1 \\  =  {16x}^{2}  + 64x + 16 + 1</h3>

We have

<h3>(g \: \circ \: f)(x) =  {16x}^{2}  + 64x + 17 \\</h3>

Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)

We have

<h3>(g \: \circ \: f)(0) = 16( {0})^{2}  + 64(0) + 17 \\</h3>

We have the final answer as

<h3>(g \: \circ \: f)(0) = 17</h3>

Hope this helps you

8 0
3 years ago
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