The easiest way is to try the point (-4,1), that is, x=-4, y=1,
to see which equation works.
b works.
The usual way to do it is to find the equation of the circle
standard form of a circle is (x-h)²+(y-k)²=r², (h,k) are the coordinates of the center, r is the radius.
in this case, the center is (-2,1), so (x+2)²+(y-1)²=r²
the given point (-4,1) is for you to find r: (-4+2)²+(1-1)²=r², r=2
so the equation is (x+2)²+(y-1)²=2²
expand it: x²+4x+4+y²-2y+1=4
x²+y²+4x-2y+1=0, which is answer b.
Answer:
Always
Step-by-step explanation:
Answer is C ig I’m sowwy if I’m wrong
Answer:
23.3225806
Step-by-step explanation:
Hello:
3x²+5x+2=0
delta = (5)²-4(3)(2)=1
x =( -5 <span>±1)/6
x= -2/3 or x=-1
t4-81=(t²)² -9² = (t²-9)(t²+9) =(t-3)(t+3)(t²+9)....(answer B)</span>