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4 years ago

Can anyone do this math

Mathematics

2 answers:

Katyanochek1 [597]4 years ago

8 0

Answer:

Yes.

Step-by-step explanation:

Option B was correct because it said that x was less than 1 so one couldn't be an answer. Knowing that you would have to pick one with an open circle showing that 1 couldn't be it so that narrows down the options to b or c. The line goes in the direction of the less than arrow (<) so that would point to answer b.

Dennis_Churaev [7]4 years ago

5 0

Answer:

Well it shows the answer, but it's B

Step-by-step explanation:

On a line graph, open circle means greater than/less than, not greater than or equal to/ less than or equal to. So we have eliminated both A and D.

The inequality say x is less than 1. The red line shows all possible solutions, so the red line must be below zero, so this means the answer must be B.

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Which of the following is the surface area of the right cylinder below?

Norma-Jean [14]

Answer: (A) 352 π units^2
Explanation in image.

Knowledge point:
Geometry - cylinder area formula

6 0

2 years ago

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

3 years ago

Will give brainliest mark plz helpp urgenttt easyy

Finger [1]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

- 4x + 3y = 12 ( add 4x to both sides )