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3 years ago

Can someone explain box plots

Mathematics

1 answer:

slamgirl [31]3 years ago

8 0

The correct answer is C because the lowest number is 4 ( out of all the numbers ), which is the dot to the above the number 4 and the largest number is 14, that is also marked by a dot above the number 18. The medians are ( the middle number ) 8 and 10, so you are going to add these to numbers together, 8 + 10 = 18, and then you have to divide it by 2, 18 ÷ 2 = 9, which means the median is 9, which is the middle line. For the 1st quartile, you have to add both the 7's and divide by 2, 7+7=14 ÷ 2 = 7, so then the 1st quartile is 7, the line closest to the 4, repeat this for the 3rd quartile, 11 + 13 = 24 ÷ 2 = 12, 3rd quartile = 12, the line closest to the number 14.

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grin007 [14]

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lisabon 2012 [21]

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3 years ago

Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m

marshall27 [118]

Answer:

1. 0.0000454

2. 0.01034

3. 0.0821

4. 0.918

Step-by-step explanation:

Let X be the random variable denoting the number of passengers arriving in a minute. Since the mean arrival rate is given to be 10,

$X \sim Poi(\lambda = 10)$

1. Requires us to compute

$P(X = 0) = e^{-10} \frac{10^0}{0!} = 0.0000454$

2. We need to compute $P(X \leq 3) = P(X =0) + P(X =1) + P(X =2) + P(X =3)$

$P(X =1) = e^{-10} \frac{10^1}{1!} = 0.000454$

$P(X =2) = e^{-10} \frac{10^2}{2!} = 0.00227$

$P(X =3) = e^{-10} \frac{10^3}{3!} = 0.00757$

$P(X \leq 3) =0.0000454+ 0.000454 + 0.00227 + 0.00757 = 0.01034$

3. The expected no. of arrivals in a 15 second period is = $10 \times \frac{1}{4} = 2.5$ . So if Y be the random variable denoting number of passengers arriving in 15 seconds,

$Y \sim Poi(2.5)$

$P(Y=0) = e^{-2.5} \frac{2.5^0}{0!} = 0.0821$

4. Here we use the fact that Y can take values $0,1, \dotsc$ . So, the event that "Y is either 0 or $\geq$ 1" is a sure event ( i.e it has probability 1 ).

$P(Y=0) + P(Y \geq 1) = 1 \implies P(Y \geq 1) = 1 -P(Y=0) = 1 - 0.0821 = 0.918$

3 0

3 years ago

Elena received a 25 dollar gift card to a fun center she drives a race car which costs 0.75 she also wants to use the grift card

Alex777 [14]

B: 4.75+0.75n ≥25

Because she has already spent 4.75 and she only has $25 and she cannot spend more than$25

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2 years ago

Which points are on the the graph equation -3x+6y+5=-7

algol [13]

-3x + 6y + 5 = -7
 -5 -5
 -3x + 6y = -12
-3x + 3x + 6y = -12 + 3x
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 6 6
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-3x + 6(-2 + 1/2x) = -12
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 0 0
 x = 0
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 +0 +0
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 (x, y) = (0, -2)

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4 years ago