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Molodets [167]
3 years ago
10

Can someone explain box plots

Mathematics
1 answer:
slamgirl [31]3 years ago
8 0

The correct answer is C because the lowest number is 4 ( out of all the numbers ), which is the dot to the above the number 4 and the largest number is 14, that is also marked by a dot above the number 18. The medians are ( the middle number ) 8 and 10, so you are going to add these to numbers together, 8 + 10 = 18, and then you have to divide it by 2, 18 ÷ 2 = 9, which means the median is 9, which is the middle line. For the 1st quartile, you have to add both the 7's and divide by 2, 7+7=14 ÷ 2 = 7, so then the 1st quartile is 7, the line closest to the 4, repeat this for the 3rd quartile, 11 + 13 = 24 ÷ 2 = 12, 3rd quartile = 12, the line closest to the number 14.

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Please answer 4 - 9 will mark brainlyist
miv72 [106K]

There are 180 degrees in a triangle

4. 38+38= 76 degrees

180-76=104

Isosceles, Obtuse

5. 65+ x+x=65

Well we know one of the x

It is 90 degrees because it is a right angle

65+90=155

180-155=25

Scalene, Right triangle

6. 71+45= 116

180-116=64

7.  Scalene, acute

8. 126+22=148

180-148=32

Scalene, Obtuse

9. 50+90=140

180-140=40

Right angle,  Scalene

Please let me know if i got anything wrong

8 0
3 years ago
If (-2, y) lies on the graph of y = 4x, then y =<br><br> -16<br> 1/16<br> 16
emmasim [6.3K]
Y = 4x
(-2,y).....x = -2

y = 4(-2)
y = -8
7 0
2 years ago
Read 2 more answers
Mexico City, Mexico, is the world's second largest metropolis and is also one of its fastest-growing cities with a projected gro
Cloud [144]

Answer:

Predicted population of Mexico City in year 2010 = 38386000

Step-by-step explanation:

Formula to be used for the population of Mexico,

P = 20.899e^{0.032t}

Where t = Duration after year 1991

P = Final population

Number of years between 2010 and 1991 = 19 years

Predicted population of Mexico city after 2010 = 20.899e^{0.032\times 19}

                                                                              = 20.899 × (1.8368)

                                                                              = 38.38633 million

                                                                              = 38.386 million

Therefore, predicted population of Mexico City in year 2010 = 38386000

5 0
3 years ago
Find the LCM of 52 and 39
qwelly [4]
Lcm of 52 and 39 is 156
8 0
3 years ago
Read 2 more answers
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is
marysya [2.9K]

Answer:

(a) 0.14%

(b) 2.28%

(c) 48%

(d) 68%

(e) 34%

(f) 50%

Step-by-step explanation:

Let <em>X</em> be a random variable representing the prices paid for a particular model of HD television.

It is provided that <em>X</em> follows a normal distribution with mean, <em>μ</em> = $1600 and standard deviation, <em>σ</em> = $100.

(a)

Compute the probability of buyers who paid more than $1900 as follows:

P(X>1900)=P(\frac{X-\mu}{\sigma}>\frac{1900-1600}{100})

                   =P(Z>3)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid more than $1900 is 0.14%.

(b)

Compute the probability of buyers who paid less than $1400 as follows:

P(X

                   =P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid less than $1400 is 2.28%.

(c)

Compute the probability of buyers who paid between $1400 and $1600 as follows:

P(1400

                              =P(-2

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1400 and $1600 is 48%.

(d)

Compute the probability of buyers who paid between $1500 and $1700 as follows:

P(1500

                              =P(-1

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1500 and $1700 is 68%.

(e)

Compute the probability of buyers who paid between $1600 and $1700 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1700 is 34%.

(f)

Compute the probability of buyers who paid between $1600 and $1900 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1900 is 50%.

8 0
3 years ago
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