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3 years ago

7

(x - 1) squaredCan you help pls

2 answers:

mixas84 [53]3 years ago

7 0

Answer: x - 1 squared would be x - 0.5

Step-by-step explanation:

1 ± 2 = 0.5

uysha [10]3 years ago

7 0

Hey :)

(x-1)^2 = (x-1) (x-1)

You can use distributive property and multiply

Or you can use binomial theorem: (a-b)^2 = a^2 - 2ab + b^2
to expand (x-1)^2

= x^2 - 2x + 1

Hope this helps!

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The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n

GarryVolchara [31]

Answer:

$(-1,1),(4,-2)$

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point $(x,y)$

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}$

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

$34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]$

Put $(x,y)=(-1,1)$

$34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34$

which is true. So, $(-1,1)$ can be a vertex

Put $(x,y)=(4,-2)$

$34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34$

which is true. So, $(4,-2)$ can be a vertex

Put $(x,y)=(1,1)$

$34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22$

which is not true. So, $(1,1)$ cannot be a vertex

Put $(x,y)=(2,-2)$

$34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22$

which is not true. So, $(2,-2)$ cannot be a vertex

Put $(x,y)=(4,-1)$

$34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30$

which is not true. So, $(4,-1)$ cannot be a vertex

Put $(x,y)=(-1,4)$

$34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70$

which is not true. So, $(-1,4)$ cannot be a vertex

So, possible points for the vertex are $(-1,1),(4,-2)$

7 0

3 years ago

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Simplify 1/9^-3? <br> A. 1/-27 <br> B. 9^3 = 729 <br> C.1/-729 <br> D. 9^-3 = -27

Natali [406]

Exponent rule : a^-b = 1 / (a^b)

1/9 ^-3 =
1 / (1/9^3) =
1 / (1^3) /(9^3) =
1 / (1/729) =
1 * 729/1 =
729

ur answer is B

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larisa86 [58]

No can’t u just search it up I feel like you’ll get the answer to this question in to time

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ziro4ka [17]

The answer to this question is 71

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Perform the indicated operation. (2x + 4)(3x + 8 )

tangare [24]

Answer: 6x^2+28x+32

Step-by-step explanation:

Distributive Property: (2x*3x)+(2x*8)+(4*3x)(4*8)=

Simplify: 6x^2+16x+12x+32=

6x^2+28x+32

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4 years ago

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